The answer is 6,61 g.
Let's see. C3H8 + 5O2 -> 3CO2 + 4H2O For every one molecule of propane burned there is four molecules of water produced. Or, this is the actuality. 1 molecule propane (1 mole C3H8/6.022 X 1023)(4 mole H2O/ 1mole C3O8) = 6.64 X 10 -24 molecules water
There are 10,886.2169 grams in 24 pounds.
There are 1000 grams in one kilogram. Therefore, 24 kilograms is equal to 24 x 1000 = 24000 grams.
24 oz = 680.4 g
For complete proper combustion of Propane: C3H8 + 5O2 = 3CO2 + 4H2O The relative atomic weights of a molecule of Propane and Oxygen are: Propane: 3 × C + 8 × H = 3 × 12 + 8 × 1 = 44 Oxygen: 2 × O = 2 × 16 = 32 Thus a molecule of propane is 44/32 = 1⅜ times heavier than a molecule of oxygen; and the same amount (number of molecules) of propane as 24 g of oxygen is 24g × 1⅜ = 33g Each propane molecule takes 5 oxygen molecules, thus: 33 g ÷ 5 = 6 3/5 g = 6.6 g If the combustion produces the poisonous carbon monoxide instead of carbon dioxide: 2C3H8 + 7O2 = 6CO + 8H2O → propane = 33g × 2/7 = 9 3/7 g ≈ 9.4 g A complete answer is thus between 6 3/5 g (6.6g) and 9 3/7 g (9.4 g) depending upon how much carbon monoxide relative to carbon dioxide is produced by the burning - the safe amount is 6.6 g.
15 grams of water in 1 tablespoon. So 24 is 360 grams
There are 1000 milligrams in one gram. Therefore, 24 milligrams is equal to 24/1000 = 0.024 grams.
24 grams.
120 grams of water is 24 teaspoons.
how many grams is 39cc?
Multiply by 28.3495231. So 24 * 28.3495231 = 680.3885544 grams.
1 gram = 1000 milligrams so 24 grams = 24*1000 = 2400 milligrams. Simple!