See Related Questions to the left "How do you prepare a solution of a specific concentration?"
Molarity (M) represents the moles of a solute per liter of a solvent. In this case, sucrose is the solute and water is the solvent. First, convert your 125g of sucrose to moles...molar mass of sucrose = 342.34 soo you have .365 moles of sucrose. Since you have exactly one L of solution, the molarity of the solution is .365 M Molarity (M) represents the moles of a solute per liter of a solvent. In this case, sucrose is the solute and water is the solvent. First, convert your 125g of sucrose to moles...molar mass of sucrose = 342.34 soo you have .365 moles of sucrose. Since you have exactly one L of solution, the molarity of the solution is .365 M
Molarity is defined as moles solute/liter of solution.Moles of solute = 2.5 moles sucrose Liters of solution = 0.5 liters Molarity (M) = 2.5 moles/0.5 liters = 5 M
Molarity = moles of solute/Liters of solution Molarity = 5 moles sucrose/0.5 Liters = 10 M ----------
1 M = 1 mole/liter. so 2 M sucrose would contain 2 moles of sucrose in 1 liter of solution.So to find the volume of solution with 1 mole sucrose:V = (1 mole) / ( 2 mole/liter) = 0.5 liter ; 0.5 liter * (1000 mL/liter) = 500 mL
Molarity is calculated as moles of solute divided by volume of solution in liters. In this case, you have 2 moles of sodium chloride in a 0.5 liter solution. So the molarity would be 2 moles / 0.5 L = 4 M.
Molarity (M) represents the moles of a solute per liter of a solvent. In this case, sucrose is the solute and water is the solvent. First, convert your 125g of sucrose to moles...molar mass of sucrose = 342.34 soo you have .365 moles of sucrose. Since you have exactly one L of solution, the molarity of the solution is .365 M Molarity (M) represents the moles of a solute per liter of a solvent. In this case, sucrose is the solute and water is the solvent. First, convert your 125g of sucrose to moles...molar mass of sucrose = 342.34 soo you have .365 moles of sucrose. Since you have exactly one L of solution, the molarity of the solution is .365 M
Molarity = moles of solute/Liters of solution Molarity = 25 moles sucrose/50 liters H2O = 0.5 M sucrose
Molarity = moles of solute/Liters of solution Find moles glucose, which is molecular formula------C6H12O6 154 grams C6H12O6 (1 mole C6H12O6/180.156 grams) = 0.8548 moles C6H12O6 Molarity = 0.8548 moles C6H12O6/1 Liter = 0.855 M glucose ---------------------------
Molarity is defined as moles solute/liter of solution.Moles of solute = 2.5 moles sucrose Liters of solution = 0.5 liters Molarity (M) = 2.5 moles/0.5 liters = 5 M
Molarity= moles/Liters To change grams to moles you divide by the mole weight which is listed on the periodic table. Mol= grams/mol weight The Mole weight of Magnesium Chloride is 59.8 grams/mol Mol=128g/59.8 Mol=2.14 Now, you put the number of moles and Liters into the equation Molarity=2.14 mol/1L Molarity=2.14 So, the molarity is 2.14 M
Molarity = moles of solute/Liters of solution Molarity = 5 moles sucrose/0.5 Liters = 10 M ----------
Is that 0.5L ? If yes, as 1L=1dm3, no. of mole= (volume)(concentration)=(0.5)(2)=1 mol
Molarity = moles of solute/volume of solution Find moles NaCl 55 grams NaCl (1mol NaCl/58.44 grams) = 0.941 moles NaCl Molarity = 0.941 moles NaCl/35 Liters = 0.027 Molarity NaCl ( sounds reasonable as 55 grams is not much in 35 Liters of water, which would be about 17.5 2 liter sodas )
1 M = 1 mole/liter. so 2 M sucrose would contain 2 moles of sucrose in 1 liter of solution.So to find the volume of solution with 1 mole sucrose:V = (1 mole) / ( 2 mole/liter) = 0.5 liter ; 0.5 liter * (1000 mL/liter) = 500 mL
Molarity is calculated as moles of solute divided by volume of solution in liters. In this case, you have 2 moles of sodium chloride in a 0.5 liter solution. So the molarity would be 2 moles / 0.5 L = 4 M.
Molarity has to deal with the concentration of solute in a concentration, and Moles per liter of the solvent is the concentration of solvent.
Molarity = moles of solute/Liters of solutionSo, get moles sodium carbonate.1.06 grams Na2CO3 (1 mole Na2CO3/105.99 grams)0.0100009435 moles Na2CO3----------------------------nowMolarity = 0.0100009435 moles Na2CO3/1 Liter= 0.01 M Na2CO3==============ask your teacher why because that much sodium carbonate does not have 0.02 molarity