Molarity=[w/GMW]*[1000/volume(in mL)] 0.5=[w/342]*[1000/100]=17.1g similarly,34.2g sucrose is to dissolved in water and made up to 100mL to make 1molar solution and 171g to make 5molar solution.
To make moles in 1 litre then divide litre by 2 = 500mls
therefore
molecular wgt of sucrose 342.29 x 1.5m = 513.43gm of sucrose in 1ltr
then divide grams by 2 = 256.71gr of sucrose in 500mls
0.22 mM=0.00022M
0.00022M x 342 (the molecular weight of sucrose)=0.07524
1/10 of a Liter is 100 mL.
So 0.07524/10=0.007524
that's your answer. 0.007524 grams
34.2 g sucrose will required toprepare such solution.
5g of sugar.
10 liters = 10,000ml,
500g / 10,000ml = 5g / 100ml.
[ 17g / (500+17)g ] * 100% = 3.29%
The answer is 50 g sucrose.
The answer is 5 g.
Ethanol is the solvent and sucrose is the solute.
Take 5 grams of calcium chloride and dissolve it in 100ml of solution to get a 5% solution of calcium chloride. The standard way to make a weight-volume solution is to take grams of the dry substance in 100ml of volume.
20mg
31M
2.0 M
See the two Related Questions to the left for the answer.The first is how to prepare a solution starting with a solid substance (and dissolving it). The second question is how to prepare a solution by diluting another solution.
Ethanol is the solvent and sucrose is the solute.
.05 L x 342 (this is the molecular weight of sucrose) x 1.75 = 29.925g
15 grams sugar per liter is the concentration, in terms of mass per volume. To express the concentration in molarity (assuming the sugar is sucrose): 15 g sucrose * (1 mole sucrose / 342 g sucrose) / 1 L = 0.0439 M aqueous sucrose
4.32
A 1% solution normally contains 1 gram of active ingredient per 100 ml of solution (weight-volume percent) Could also be 1gm per 100 gms (weight-weight percent)- but normally weight-volume is used.
A 5% sucrose solution has 5 grams of sucrose in every 100 grams of solution. As 1mL of water has a mass of 1 gram, you should dissolve 5 grams of sucrose in 95 mL of water.
Add sugar and stir until no more sugar dissolves
400 mls would require 40g of glucose for a 10% solution and thus 20g for a 5% solution.
I am assuming you are refering to a one molar solution. I am also assuming that you have simplified the problem, because sucrose takes up space in water, so a 1 molar solution of sucrose would have less than 1000mL of water. I do not know the what volume of solution is desired, so I will use one liter in my equation. For the sake of organization: 1L sucrose solution * (0.2 moles sucrose/ 1L) * (342.12 g/ 1 mole sucrose) = 68.42 g sucrose In one liter there will be 1000 mL of water (if you simplify the equation so that sucrose doesn't displace any water). In summary: in a 0.2 molar solution of sucrose, there are 68.2 grams of sucrose.
Take 5 grams of calcium chloride and dissolve it in 100ml of solution to get a 5% solution of calcium chloride. The standard way to make a weight-volume solution is to take grams of the dry substance in 100ml of volume.
1000 grams of water and 2 grams of sugar - sucrose