0
How many grams of sugar must be added to 60 grams of a solution that is 32 percent sugar to obtain a solution that is 50 percent sugar?
Wiki User
∙ 8y ago
40.8 grams
Wiki User
∙ 8y ago
Add your answer:
Earn +20 pts
How many grams of glucose must be added to 525 g of 2.5 percent leg mass glucose solution?
how many grams of glucose must be added to 525g of 2.5 percent leg mass glucose solution?and give the furmela?
How much water must be added to 12 grams of a 90 percent iodine solution to produce a 25 percent iodine solution?
12*(90%)=10.8=X*.25 10.8/.25=X=43.2 43.2-12=31.2 31.2 grams of water must be added
How much water needs to be added to a 5g vial of drug powder to make a 2.5 percent solution?
195 grams.
Does the Mass mass percent concentration measures grams of solute per grams of solvent?
No, not exactly.Mass mass percent concentration measures grams of solute per 100 grams of solution (= solvent + solute)Example:58.5 g NaCl (solute) added to941.5 g H2O (solvent) gives you1000.0 g solution of 5.85% NaCl (= 100%*58.5/1000.0),which is about a 1.0 mol/L NaCl solution.
What is the percentage by mass of salt solution prepared by dissolving 11 grams of salt in 80 grams of solution with solution?
The percent concentration is 13,75 %.
How much grams of ammoinum thiocyanate to be added in 100ml of water to get 1 percent of solution?
Very simply 1g of ammonium thiocyanate and 100g (100ml) of water!
How much grams of ferric chloride to be added in 100ml of water to get 2 percent solution?
Very simply 2g of ferric chloride and 100g (100ml) of water!
How much of a 37 percent formaldehyde solution should be put into 900 ml of water to make a 10 percent formaledhyde solution?
If the percentages specified are by mass and the 900 ml of water are assumed to be at standard temperature and pressure, this problem can be solved as follows: The 900 ml of water will have a mass of 900 grams. Call the unknown mass of the 37 percent solution to be added m. this will contain 0.37m grams of formaldehyde and 0.63m grams of water, and 0.37m/(900 + m) = 0.10. Then, multiplying both sides by (m + 900), 0.37m = 0.10m + 90, or 0.27m = 90, or m = 3.3 X 102 grams of the 37 % solution to be added, to the justified number of significant digits.
What is the grams in 250 ml of a 5 percent solution?
12.5
How many grams of medication will 500 ml of a 10 percent solution contain?
50 grams
How 10 percent DNS was prepared?
You have 100 grams of pure dextrose and 9 grams of pure sodium chloride added to one liter of distilled water. The solution is sterilized and packed in polypropylene or polyethylene bottles.
An iron ore sample is found to be 35.00 percent Fe by mass How many grams of ore is needed to obtain 454.0 grams of Fe?
The number of grams of ore that is needed to obtain 454.0 grams of Fe is 1297 grams. The answer was achieved by dividing 454.0 grams by 35 percent.
