16777214
254
The default mask class B is 255.255.0.0 and this makes 16 bits available for hosts
16
254 host as 172.16.32.0/24
with the default subnet mask, the number of clients in a class A network is: 16,777,214
Class C have 8 bit use for host address. So we have 2^8=256 address, but the first and the last one is not used for host => 256-2=254 PC (or host)
65,534
15 or 16.
20
62 hosts.
There are 2^24 host in class A but (2^24)-2 hosts are valid since the first and last address are reserved .
class A ip has 16777216 host but valid hosts are only 16777214.(2^24-2)So answer is 16777214 hosts