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IPv4 has 32-bits classified into 4 bytes out of which each byte is divided into network or hosts. Thus, it can have any combination like 1 host, 3 networks or 2 host, 2networks etc.

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Q: How many host bits in an IP address of 192.168.254.192?
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Related questions

How many bits in a class b ip address are used for the host address?

16


How many host address are there for an address with 21 bits for the network address?

2046 Breakdown: 11111111.11111111.11111000.00000000 /21 - 21 bits in network address represented by ones in binary address above. Leaves 2^11th power host addresses left (the zeros to the right). Equals 2048 host addresses minus the two reserved addresses = 2046


How many bits are borrowed from a class B host address to create 30 new subnets?

5 bits are necessary to create up to 30 subnets.


How many bits are borrowed from a Class C host address to create 6 new sub-nets?

20


How many contiguous class c addresses are required to extend the host address by four bits?

15 or 16.


How do you know how many bits represent the network portion and the host portion?

When we express an IPv4 network address, we add a prefix length to the network address. The prefix length is the number of bits in the address that gives us the network portion. For example, in 172.16.4.0 /24, the /24 is the prefix length - it tells us that the first 24 bits are the network address. This leaves the remaining 8 bits, the last octet, as the host portion.


If you borrow 10 host bits from a Class B network address how many usable hosts are left?

62 hosts.


How many address in IPv4 address?

32 bits in a IPv4 address


How many bits are available for class b host ip address using a default subnet mask?

The default mask class B is 255.255.0.0 and this makes 16 bits available for hosts


How many bits of address bus are required to address 1mb memory?

You need 20 bits of address bus to address 1 Mb of memory.


How many subnets can you have in a class C network with a 26 bit mask?

A Class C IP address has 24 bits for network and 8 bits for host. So to have a subnet mask of 26 bits, you will need to use 2 bits from host part.Number of subnets is given by the formula : 2^(no. of bits used from host part).Hence number of subnets in this case would be = 2^2 = 4.For e.g. if the class C IP address is 200.168.210.0the 4 subnet addresses would be :11001000.10101000.11010010.00000000 = 200.168.210.011001000.10101000.11010010.01000000 = 200.168.210.6411001000.10101000.11010010.10000000 = 200.168.210.12811001000.10101000.11010010.11000000 = 200.168.210.192Note: The digits in bold are the mask bits.


How many bits of mask are required to provide 30 host addresses?

5 bits