A Class C IP address has 24 bits for network and 8 bits for host. So to have a subnet mask of 26 bits, you will need to use 2 bits from host part.
Number of subnets is given by the formula : 2^(no. of bits used from host part).
Hence number of subnets in this case would be = 2^2 = 4.
For e.g. if the class C IP address is 200.168.210.0
the 4 subnet addresses would be :
11001000.10101000.11010010.00000000 = 200.168.210.0
11001000.10101000.11010010.01000000 = 200.168.210.64
11001000.10101000.11010010.10000000 = 200.168.210.128
11001000.10101000.11010010.11000000 = 200.168.210.192
Note: The digits in bold are the mask bits.
Given a Class C network: 200.1.1.0 We want 5 subnets, each with 30 hosts on it. How many bits to borrow ? How many bits to leave? What is the subnet mask? ( in dot notation and in CIDR notation)
255.255.255.0
14 (+2 for network & host).
255.255.252.0
255.255.252.0
What if your company is assigned a network address of 150.50.0.0 you need to create 4 subnets all having access to the internet what is the correct subnet mask for the network
A subnet mask that would divide the 172.31.0.0 network into as many subnets as possible and support 600 uers on each subnet would be 255.255.255.0. Each subnet can communicate with each other through the gateway.
A subnet mask that would divide the 172.31.0.0 network into as many subnets as possible and support 600 uers on each subnet would be 255.255.255.0. Each subnet can communicate with each other through the gateway.
Subnet Mask provides Network & Class Identificationfor an IP Address.
Since this is a Class C address, the default network mask is 255.255.255.0.Since this is a Class C address, the default network mask is 255.255.255.0.Since this is a Class C address, the default network mask is 255.255.255.0.Since this is a Class C address, the default network mask is 255.255.255.0.
255.255.252.0
A, B and D are subnets. C is not. IP addresses A and D are both Class B subnets. Class B addresses normally have a subnet mask of 255.255.0.0. The first two bits of a class B network are always 10 which leaves 14 bits for the network prefix, thus allowing up to 16,384 separate Class B networks (including 139.233.0.0 and 190.233.0.0). The last 16 bits denote the host number thus there can be up to 65,536 hosts per network. By specifying a subnet mask of 255.255.255.0 the network can be divided into as many as 256 separate subnets each with 256 hosts. IP address B is a Class A subnet. Class A addresses normally have a subnet mask of 255.0.0.0. The first bit of a class A network is always 0, which leaves 7 bits for the network prefix, thus allowing up to 127 Class A networks (including 10.0.0.0). The last 24 bits denote the host number thus there can be up to 16,777,216 hosts per network. By specifying a subnet mask of 255.255.255.0, the hosts can be divided into as many as 65,536 separate subnets each with up to 256 hosts. IP address C is a Class C address, but is not a subnet. Class C addresses normally have a subnet mask of 255.255.255.0. The first three bits in a Class C network are always 110, leaving 21 bits for the network prefix, thus allowing up to 2,097,152 Class C networks (including 192.168.0.0). The last 8 bits denote the host number thus there can be up 256 hosts per network. To make a subnet out of a Class C address you must have a subnet mask of 255.255.255.X, where X may be 192, 224, 240, 248 or 252. That is, 2, 3, 4, 5 or 6 bits to denote the subnet and the remaining bits to denote the hosts. Thus a subnet mask of 255.255.255.192 would allow as many as 4 subnets each with up to 64 hosts, while a subnet mask of 255.255.255.240 would allow as many as 16 subnets each with up to 16 hosts. It should be noted that the maximum number of hosts is actually 2 less than the figures shown above. This is because the host address with all 0 bits is reserved for network address while the host address with all 1 bits is reserved for broadcasting.