The molar mass of C2H6 is 30 {(12*2)+(1*6)}.
The number of moles(n)=mass/molar mass
n=9.3 g/ 30 g mol-1 =0.31 mol.
The number of molecules of C2H6 =n* Avogadro number(L)= 0.31*6.022*1023= 1.86682*1023
The no. of atoms in one mole of C2H6=8
The no. of atoms in 0.31 moles of C2H6=8*1.86682*1023 =14.93456*1023 =1.49*1024
1.0 mol C2H6 has 2.0 mole of carbon atoms in it.
1.0 mol = 6.02 x 1023 (same as 1.0 dozen = 12)
Therefore, there are 1.2 x 1024 mol C atoms in 1.0 mole of ethane.
(keeping your 2 significant figures)
For this you need the atomic (molecular) mass of C6H6. Take the number of moles and multiply it by the Atomic Mass. Divide by one mole for units to cancel. C6H6=78.1 grams
5.6 moles C6H6 × (78.1 grams) = 437.36 moles C6H6
1.405x10-2 * 6.022x10^23= 8.46091x10^21 molecules
sigfigs- 8.461x10^21 molecules of C6H6
62. 3 g C6H6 (1 mole C6H6/78.018 grams)(6 mole H/1 mole C6H6)(6.022 X 1023/1 mole H)
= 2.89 X 1024 hydrogen atoms
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0.273 grams C2H6O (1 mole C2H6O/40.068 grams)(6.022 X 1023/1 mole C2H6O)
= 4.10 X 1021 molecules of ( ethanol?/dimethyl ether? ) C2H6O
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The number of molecules in 23,0 grams of C6H12 is 1,6457.10e23.
4.44 x10^24 atoms C
4.035x10^22 molecules of benzene
4.44×10^24 atoms of Carbon
An international ounce has 28,349 523 125 g.
One gram is = 0.0235669 ounces One ounce is = 28.349 523 grams 125g= 4.409245 oz
.523 kHz = 523 Hz
1 ounce [troy] = 31.103 476 8 gram 1 ounce = 28.349 523 125 gram
grams divided by 28.349 523 125 = ounces so 75/28.349 = 2.646 oz
523 - 378 = 145
There are 1000 metres in one kilometre. Therefore, 523 metres is equal to 523/1000 = 0.523 kilometres.
there are 523
There are 2.54 centimetres in one inch. Therefore, rounded to two decimal places, 523 centimetres is equal to 523/2.54 = 205.91 inches.
there are 20.590551181102363in in 523mm
523
523 Rakuh