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The chemical formula of sodium sulfideis Na2S.

The sodium cation is Na+ and the sulfide anion is S2-.

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11y ago

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What element can combine with sulfur to make an ionic compound?

Many metals form ionic sulfides containing the S2- ion, , for example sodium, Na2S sodium sulfide. Iron forms a sulfide, FeS, iron(II) sulfide and a disulfide, containing the S22- ion, iron, iron(II) disulfide, FeS2 , "fools gold"


How many sodium atoms are needed to form an ionic bond with sulfur?

One sodium atom is needed to form an ionic bond with one sulfur atom. Sodium typically loses one electron to form a cation with a +1 charge, while sulfur gains two electrons to form an anion with a -2 charge.


Is table salt an example of a binary ionic compound.?

Yes, table salt (sodium chloride, NaCl) is an example of a binary ionic compound. It is composed of just two elements: sodium (Na) and chlorine (Cl), with sodium ion carrying a positive charge and chlorine ion carrying a negative charge.


How many atoms in sodium sulfide?

In one formula unit of sodium sulfide (Na2S), there are 3 atoms - 2 atoms of sodium (Na) and 1 atom of sulfur (S).


How many potassium are needed to balance the charge of on sulfide ion?

Normally, 2 K+ ions are required for making a stable ionic bond with one S 2- anion. The compound formed would be Potassium Sulfide (K2S).


How many potassium ions are needed to balance the charge of one sulfide ion and why?

You would need two potassium ions to balance the charge of one sulfide ion. Potassium has a charge of +1, while sulfide has a charge of -2, so two potassium ions with a total charge of +2 would balance the charge of one sulfide ion with a charge of -2.


How many potassium ions are needed to balance the charge of one sulfide ion Explain?

One potassium ion is needed to balance the charge of one sulfide ion. This is because potassium has a +1 charge and sulfide has a -2 charge. Therefore, one potassium ion with a +1 charge will neutralize the -2 charge of one sulfide ion, resulting in a net charge of 0.


Have many potassium ions are needed to balance the charge of one sulfide ion?

Two potassium ions are needed to balance the charge of one sulfide ion because the sulfide ion has a charge of -2, while each potassium ion has a charge of +1. Two potassium ions with a total charge of +2 will balance the -2 charge of one sulfide ion.


How many moles are there in 73.5 g of sodium sulfide?

To determine the number of moles in 73.5 g of sodium sulfide (Na2S), you first need to calculate the molar mass of Na2S, which is 78.04 g/mol. Then divide the given mass by the molar mass to find the number of moles. Therefore, 73.5 g / 78.04 g/mol = 0.942 moles of sodium sulfide.


How many potassium ions are needed to balance the charge of one sulfide ion balance ions?

so it can be balanced out


How many potassium ions are needed to balance the charge of one sufide ion?

Two potassium ions are needed to balance the charge of one sulfide ion. Potassium has a +1 charge and sulfide has a -2 charge, so two potassium ions with a +1 charge each are required to balance the -2 charge of the sulfide ion.


How many chargers does sodium have?

Sodium typically has a +1 charge.