Three (3)
Here is the equation
Al^3+ + 3Br^- = AlBr3
3
Two bromide ions can combine with one barium cation to form an ionic compound, because a barium cation has an electrical charge of +2, while a bromide anion has an electrical charge of -1.
2.03mol
133
Three
Aluminum chloride contains 3 chlorine atoms per molecular unit. Therefore, in 3 moles there are 3 times Avogadro's number of chloride ions = 1.807 X 1024.
Two bromide ions can combine with one barium cation to form an ionic compound, because a barium cation has an electrical charge of +2, while a bromide anion has an electrical charge of -1.
Bromine has -1 charge and Lithium has +1 charge. Therefore,only one lithium ion is required to react with a bromine ion.
There are 3 ions in the formula Al2SO4 (2 aluminum and 1 sulfate), but this formula is wrong. The formula of aluminum sulfate is Al2(SO4)3 which contains 5 ions: 2 aluminum ions and 3 sulfate ions.
Aluminum ions are positive, and have three neutrons in it.
2.03mol
Aluminum is 3+ and chloride is 1-. So, you need 3 chloride ions to neutralize 1 aluminum ion.
133
There are two ions, aluminum is one ion and chloride is the other ion
The answer will depend on how much bromine it reacted with or how much auminium bromide was produced. Since this information is not provided, it is not possible to answer the question.
It is a lattice. There are 6 cl- ions around a sodium ion.
3 Fluorine atoms are required for 1 aluminum atom.
The formula for aluminum oxide is Al2O3, which means that, if aluminum oxide is ionically bonded, every formula mass of aluminum oxide contains three O-2 ions. In this instance, 0.65 formula masses of aluminum oxide would contain 3 X 0.65 or 1.95 moles of O2-. If aluminum oxide were covalently bonded, it would not contain any O-2 ions.