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How many chloride ions are in 1.50 mol of aluminum chloride?
AlCl3 = 3 chloride ions per molecule and so 3 x 1.5 x 6.022 x 1023 2.7099 x 1024
What is the number of chlorine ions in 0.5mol of titanium 3 chloride?
Titanium (III) chloride has the formula TiCl3 and therefore contains three chloride ions per formula unit. The number of chloride ions in 0.5 mol is therefore (3/2) X Avogadro's Number or 9 X 1023, to the justified number of significant digits.
The molar mass of aluminum chloride is?
The molar mass of aluminum chloride (AlCl3) is approximately 133.34 g/mol.
What is the maximum mass of aluminum chloride that can be formed when reacting 15.0 g of aluminum with 20.0 g of chlorine?
The balanced chemical equation for the reaction between aluminum and chlorine to form aluminum chloride is 2Al + 3Cl2 → 2AlCl3. Using the molar masses of aluminum and chlorine, we find that 15.0 g of aluminum is equivalent to 0.56 mol and 20.0 g of chlorine is equivalent to 0.28 mol. Since aluminum and chlorine react in a 2:3 ratio, 0.56 mol of aluminum would require 0.84 mol of chlorine. Therefore, the limiting reactant is chlorine, and the maximum mass of aluminum chloride that can be formed is 59.6 g.
Determine the number of moles present in 32.5 g aluminum chloride?
To determine the number of moles, you need to divide the given mass (32.5 g) by the molar mass of aluminum chloride (AlCl3). The molar mass of AlCl3 is 133.34 g/mol. So, 32.5 g / 133.34 g/mol ≈ 0.244 moles of aluminum chloride.
How many chloride ions are in 1.50 mol of aluminum chloride?
AlCl3 = 3 chloride ions per molecule and so 3 x 1.5 x 6.022 x 1023 2.7099 x 1024
What is the number of chlorine ions in 0.5mol of titanium 3 chloride?
Titanium (III) chloride has the formula TiCl3 and therefore contains three chloride ions per formula unit. The number of chloride ions in 0.5 mol is therefore (3/2) X Avogadro's Number or 9 X 1023, to the justified number of significant digits.
The molar mass of aluminum chloride is?
The molar mass of aluminum chloride (AlCl3) is approximately 133.34 g/mol.
Which best compares 1 mol of sodium chloride to 1 mol of aluminum chloride?
Each compound has a different molar mass.
What is the molar mass for aluminum chloride?
The molar mass of aluminum chloride (AlCl3) is approximately 133.34 g/mol. This is calculated by adding together the atomic masses of aluminum (26.98 g/mol) and chlorine (35.45 g/mol) in the compound.
The molar mass of aluminum chloride is grams?
The molar mass of anhydrous aluminum chloride is 133,34 grams.
How many moles present in 32.5 g aluminum chloride (AlCl3).?
To find the number of moles of aluminum chloride in 32.5 g, you first need to calculate the molar mass of AlCl3, which is 133.34 g/mol. Then, divide the given mass by the molar mass to get the number of moles. In this case, 32.5 g ÷ 133.34 g/mol ≈ 0.244 moles of aluminum chloride.
What is the maximum mass of aluminum chloride that can be formed when reacting 15.0 g of aluminum with 20.0 g of chlorine?
The balanced chemical equation for the reaction between aluminum and chlorine to form aluminum chloride is 2Al + 3Cl2 → 2AlCl3. Using the molar masses of aluminum and chlorine, we find that 15.0 g of aluminum is equivalent to 0.56 mol and 20.0 g of chlorine is equivalent to 0.28 mol. Since aluminum and chlorine react in a 2:3 ratio, 0.56 mol of aluminum would require 0.84 mol of chlorine. Therefore, the limiting reactant is chlorine, and the maximum mass of aluminum chloride that can be formed is 59.6 g.
Determine the number of moles present in 32.5 g aluminum chloride?
To determine the number of moles, you need to divide the given mass (32.5 g) by the molar mass of aluminum chloride (AlCl3). The molar mass of AlCl3 is 133.34 g/mol. So, 32.5 g / 133.34 g/mol ≈ 0.244 moles of aluminum chloride.
When 0.440 mol of aluminum are allowed to react with an excess of chlorine gas Cl2 how many moles of aluminum chloride are produced?
The balanced chemical equation for the reaction between aluminum and chlorine is 2Al + 3Cl2 -> 2AlCl3. This means that for every 2 moles of aluminum that react, 2 moles of aluminum chloride are produced. Therefore, if 0.440 mol of aluminum is used, it will produce 0.440 mol of aluminum chloride.
What is the molar mass of chloride?
you mean to say chlorine... and it 35.45g/mol
What is the formula mass of a molecule of aluminum chloride if the mass number of aluminum is 27 and chlorine is 35?
The molar mass of aluminum (Al) is 27 g/mol and chlorine (Cl) is 35 g/mol. Aluminum chloride (AlCl3) has one aluminum atom and three chlorine atoms. Therefore, the formula mass (or molar mass) of aluminum chloride is 27 (Al) + 3(35) (3Cl) = 106 g/mol.
