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What is the number of moles present in 32.5 g aluminum chloride?
To find the number of moles, you need to divide the mass of the substance by its molar mass. The molar mass of aluminum chloride (AlCl3) is 133.34 g/mol. So, for 32.5 g of aluminum chloride, the number of moles would be 32.5 g / 133.34 g/mol = 0.243 moles.
How many moles of chloride ions are in 0.2520g of aluminum chloride?
To find the number of moles of chloride ions in aluminum chloride, you first need to convert 0.2520g of aluminum chloride to moles. Then, since there are three chloride ions per one aluminum chloride molecule, you would multiply the number of moles of aluminum chloride by 3 to find the moles of chloride ions.
Choose the correct formula for aluminum chloride?
The chemical formula for aluminum chloride is ALCL3. The number 3 is written below the line as a subscript.
You are given 34.0 g of aluminum and 39.0 g of chlorine gas. If you had excess chlorine how many moles of aluminum chloride could be produced from 34.0 g of aluminum?
First, calculate the number of moles of aluminum in 34.0 g using its molar mass. Then, determine the limiting reactant by converting the moles of aluminum to moles of aluminum chloride using the mole ratio from the balanced chemical equation. Finally, calculate the moles of aluminum chloride that can be produced based on the limiting reactant.
How many chloride ions are there in 3 mol of aluminum chloride?
Aluminum chloride contains 3 chlorine atoms per molecular unit. Therefore, in 3 moles there are 3 times Avogadro's number of chloride ions = 1.807 X 1024.
What is the number of moles present in 32.5 g aluminum chloride?
To find the number of moles, you need to divide the mass of the substance by its molar mass. The molar mass of aluminum chloride (AlCl3) is 133.34 g/mol. So, for 32.5 g of aluminum chloride, the number of moles would be 32.5 g / 133.34 g/mol = 0.243 moles.
What is the oxidation number of aluminum in aluminum chloride?
The oxidation number of aluminum in aluminum chloride (AlCl3) is +3. Aluminum typically has an oxidation number of +3 when it forms ionic compounds.
How many moles present in 32.5 g aluminum chloride (AlCl3).?
To find the number of moles of aluminum chloride in 32.5 g, you first need to calculate the molar mass of AlCl3, which is 133.34 g/mol. Then, divide the given mass by the molar mass to get the number of moles. In this case, 32.5 g ÷ 133.34 g/mol ≈ 0.244 moles of aluminum chloride.
How many moles of chloride ions are in 0.2520g of aluminum chloride?
To find the number of moles of chloride ions in aluminum chloride, you first need to convert 0.2520g of aluminum chloride to moles. Then, since there are three chloride ions per one aluminum chloride molecule, you would multiply the number of moles of aluminum chloride by 3 to find the moles of chloride ions.
Choose the correct formula for aluminum chloride?
The chemical formula for aluminum chloride is ALCL3. The number 3 is written below the line as a subscript.
How many molecules are in 2.0 grams of aluminum chloride?
To determine the number of molecules in 2.0 grams of aluminum chloride, first calculate the molar mass of aluminum chloride (AlCl3). The molar mass is 133.34 g/mol. Next, convert the given mass (2.0 g) to moles using the molar mass. Finally, use Avogadro's number (6.022 x 10^23) to find the number of molecules.
You are given 34.0 g of aluminum and 39.0 g of chlorine gas. If you had excess chlorine how many moles of aluminum chloride could be produced from 34.0 g of aluminum?
First, calculate the number of moles of aluminum in 34.0 g using its molar mass. Then, determine the limiting reactant by converting the moles of aluminum to moles of aluminum chloride using the mole ratio from the balanced chemical equation. Finally, calculate the moles of aluminum chloride that can be produced based on the limiting reactant.
What is the oxidation number of aluminum chloride?
The oxidation number of aluminum in aluminum chloride (AlCl3) is +3. This is because each chlorine atom has an oxidation number of -1, and there are three chlorine atoms bonded to the aluminum atom, resulting in a total charge of -3 for the chlorine atoms. For the compound to be neutral, the aluminum atom must have an oxidation number of +3.
How many chloride ions are there in 3 mol of aluminum chloride?
Aluminum chloride contains 3 chlorine atoms per molecular unit. Therefore, in 3 moles there are 3 times Avogadro's number of chloride ions = 1.807 X 1024.
How many moles of aluminum are present in an aluminum cylinder with a mass of 15 g?
To determine the number of moles of aluminum present, we need to first determine the molar mass of aluminum, which is approximately 26.98 g/mol. We can then use the formula: moles = mass / molar mass. Plugging in the values, we get moles = 15 g / 26.98 g/mol ≈ 0.56 moles of aluminum.
What are number of neutrons present in aluminum?
14
How many atoms of aluminum are there in a sample of aluminum sulfide with a mass of 100 g?
Aluminum sulfide has a molar mass of 150.16 grams per mole. This means there are 0.666 moles present, or 4.01 E23 molecules. Each molecule of Al2S3 has 2 aluminum atoms, so there are 8.02 E23 atoms of aluminum present.
