0.244mol
0.244 mol (:
4 moles
There are 10 moles present in 585 g of sodium chloride.
Aluminum chloride contains 3 chlorine atoms per molecular unit. Therefore, in 3 moles there are 3 times Avogadro's number of chloride ions = 1.807 X 1024.
.21 moles/liter * .0655 L = 0.013755 moles AlCl3 .013755 * 3 moles Cl / 1 mole AlCl3 = 0.041265 moles Cl * avagadro's number = number of chloride ions
0.244 mol (:
1,075 moles of aluminium chloride are obtained.
4 moles
There are 10 moles present in 585 g of sodium chloride.
Aluminum chloride contains 3 chlorine atoms per molecular unit. Therefore, in 3 moles there are 3 times Avogadro's number of chloride ions = 1.807 X 1024.
The Answer is.56 moles OR 0.56 moles
.21 moles/liter * .0655 L = 0.013755 moles AlCl3 .013755 * 3 moles Cl / 1 mole AlCl3 = 0.041265 moles Cl * avagadro's number = number of chloride ions
9
This depends on the solution concentration.
The molecular mass of AlCl3 is 133,340 538 6 g.
The number of atoms in 1,2 moles of pure aluminum is 7,2265690284.1023.
10 moles of sodium chloride have 584,397 g.