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Q: How many joules are needed to change the temperature of 1 gram of water by 1C?
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Approximately how many Joules of heat are needed to completely change 10.0 grams of ice to water at the melting point temperature?

134 joules. You're very welcome for answering your question.


How many joules are needed to change the temperature of 100 g of water from 20 degrees Celsius to 40 degrees celsius?

8.200 J


What is an amount of water whose temperature would change by 15 degrees Celsius when it absorbs 2646 joules of heat energy?

The amount of water whose temperature would change by 15 degrees Celsius when it absorbs 2646 joules of heat energy is 42,2g H2O.


How much energy would be needed to raise the temperature of 10 kilograms of water from 273 to 373 K?

10ml's of water is equal to 10cm3 of water. 10cm3 of water has a mass of 10g. The specific heat of water is 4.134 J/K. The change in temperature is 1 degree Kelvin. Use Q=mC∆T which means Heat= (Mass)(Specific Heat)(Change in Temperature) Q= (10)(4.134)(1) Q=(10)(4.134) Q=41.34 Joules


If it takes 31500 joules of heat to warm 750 g of water what was the temperature change?

10 degrees Celsius


How many joules of heat are needed to change the temp of 40 g of water?

167.2J if it doesn't have to do with phase changes.


How much heat in joules is needed to raise the temperature of 4.0 L of water from 0 degrees Celsius to 70.0 degrees Celsius?

It takes 4.186 Joules to heat one gram of water by 1-degree Celsius. 4.186 * 4000 = 16,744 Joules to heat 4 kilos of water by 1-degree. 16,744 * 70 = 1,172,080 Joules. The above assumes that one litre of water weighs exactly 1 Kilogram.


The number of kilojoules needed to raise the temperature of 32.0 g of water from 12.0 degree centigrade to 54.0 degree centigrade is?

q(Joules) = mass * specific heat * change in temperature q = 32.0 grams H2O * 4.180 J/gC *(54.0 C - 12.0 C) = 5617.92 Joules this is, of course 5.62 kilojoules


How many joules are needed to change 219.70 g of water at 72.7 C to steam at 100 C?

This value is 22,418 kJ.


What is the total amount of heat energy in joules absorbed by 25.0 grams of water when the temperature of the water increased from 24.0 C to 36.0 C?

2520 Joules = (X)(4.180J/gC)(30C-10C) 2520J = 83.6X 30.14 grams of water.


How much energy is needed to reduce water temperature from 15 degrees to 14 degrees?

1 calorie increases 1 gram of water by 1 degree celsius. 4.18 Joules are needed to increase the temperature of 1 gram of water by 1 degree celsius. To reduce the 1 gram of water 1 degree celsius it would have to give off 1 calorie of energy. To calculate the energy multiply the mass in grams of water by 4.18 and by the change in temperature. The energy = 4.18 x m x change in T. The answer is in Joules. If you are using calorie as the unit of energy, replace 4.18 J by 1 C. Note that food is measured in kilocalories (Calories) not metric calories.


How many joules are required to boil 21.1 g of water at 100 C?

The needed heat is 47,65 Joules.