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2,26 Kj are necessary
That completely depends on how much steam there is. (mass)
1
200 joules of any other type of energy can be converted to 200 joules of heat.
Approx 2940 Joules.
46 calories (or 192, 464 joules) for each Celsius degree.
2,26 Kj are necessary
46 calories (or 192, 464 joules) for each Celsius degree.
419.1 Joules are required to heat one gram of liquid water from 0.01 degC to 100 deg C. So the answer is 419.1*46 = 19278.6
46 calories (or 192, 464 joules) for each Celsius degree.
0000000000000000.11 joules
In principle, those two things measure different things (mass, and energy). To get the mass associated with a certain amount of energy, divide the number of joules (1 kJ = 1000 joules) by the square of the speed of light, i.e., divide by 9 x 1016 (m2/sec2). The answer is in kilograms; you an multiply this answer by 1000 to convert into grams.
50.75 joules of energy equates to about 12.1 calories.
About 670 joules.
Assuming no state change:ΔH = mCΔTm = 4.60 gC = 4.184 J/(g * K)ΔT = 100.0 KΔH = 1920 J = 1.92 kJ
Voltage is electrical pressure and Joules is a power rating so other info is needed
39.2 joules of potential energy.