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46 calories (or 192, 464 joules) for each Celsius degree.

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Q: How many joules of energy are necessary to heat a sample of water with a mass of 46.0 grams for 0.0?
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What energy is measure in?

A: Energy is measured in joules and kilojoules. One joule is the amount of energy needed to lift 100 grams to 1 kiliogram.


The specific heat of gold is 0.131 Joules per gram. Celsius How much energy is required to heat 1.3 grams of gold from 25 Celsius to 46 Celsius?

0.131 joules/gram'C x 1.3 grams x (46-25)'C = 3.5763 joules


How many joules of energy are necessary to heat sample of water with a mass of 46.0 grams from 0.0 to 100 C?

Assuming the water is liquid, the specific heat is about 4.186 joule/gram·°C, so to heat 46 grams of water would take about 192.556 joules/°C. The specific heat of ice is about 2.100 Joules/g·°C so heating 46 g of frozen water would take about 96.6 joules/°C. The specific heat of steam is about 2.020 Joules/g·°C so heating 46 g of water vapor would take about 92.2 joules/°C.


How do you turn grams into joules?

You cannot do so directly. They measure completely different things. Grams is a measurement for mass while kcal is a measurement of energy (or something like that). The point is they are two different measuring metrics for two different metrics. It will be like asking how to convert inches into minutes


What amount of heat energy is required to raise the temperature of 45 pounds of lead from 62 degrees to 100 degreesF?

Specific heat of lead = 0.160 J/gC 45 pounds (454 grams/ 1 pound) = 20430 grams Use. q(Joules) = mass * specific heat * change in temp. q = (20430 grams)(0.160 J/gC)(100 C - 62 C) = 1.2 X 10^5 Joules ------------------------- or ------------------------- 1.2 X 10^5 Joules (1 calorie/4.184 Joules) = 29688 calories

Related questions

How many joules are necessary to heat a sample of water with a mass of 46.0 grams from 0.0?

46 calories (or 192, 464 joules) for each Celsius degree.


How many joules of energy are necessary to heat a sample of water with a mass of 46.0 grams from 0.0 celsius to 100.0?

419.1 Joules are required to heat one gram of liquid water from 0.01 degC to 100 deg C. So the answer is 419.1*46 = 19278.6


A sample of H½O with a mass of 46.0 grams has a temperature of?

96.3 Joules


How many joules of energy are necessary to heat a sample of water with a mass of 4.60 grams from 0.0 to 100.0?

Assuming no state change:ΔH = mCΔTm = 4.60 gC = 4.184 J/(g * K)ΔT = 100.0 KΔH = 1920 J = 1.92 kJ


How many joules are needed to melt 2 grams of water?

2,26 Kj are necessary


A sample of h2o with a mass of 46.0 grams has a temperature of 100 c how many joules of energy are necessary to boil the water?

Using 2260 J/g as the ∆Hvaporizationq = 46.0 g x 2260 J/g = 103,960 J = 104 kJ (to 3 sig. figs)


A sample of H20 with a mass of 46.0 grams has a temperature of 100 c How many joules of energy are necessary to boil the water?

The heat of vaporization is about 2258 joules/gram46 x 2258 = 103,868 J ~ 103.9 kJ(Using the rounded value 2260 joules per gram, about 104 kJ)it is already at boiling point so in theory zero energy is required.I think the question is asking what energy is required to free the water from its liquid state to the vapour state.At 101325Pa, (1 atmosphere in old money), the latent heat of evaporation of water is 2256.7 J/g.So 2256.7 * 46 = 103808 Joules


Is mass measured in joules?

No, a Joule is a unit of energy. Mass is measured in kilograms (or grams)


What energy is measure in?

A: Energy is measured in joules and kilojoules. One joule is the amount of energy needed to lift 100 grams to 1 kiliogram.


What is the kinetic energy of an object with an mass of 5 grams and a velocity of 1000ms?

The object's kinetic energy is 2,500 joules.


How many joules of energy are necessary to heat a sample of water with a mass of 46.0 grams from 0.0 degrees celsius to 100 degrees celsius?

42 J


The specific heat of gold is 0.131 Joules per gram. Celsius How much energy is required to heat 1.3 grams of gold from 25 Celsius to 46 Celsius?

0.131 joules/gram'C x 1.3 grams x (46-25)'C = 3.5763 joules