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To answer this question, you need ethanol's specific heat. I looked it up for you, and it's 2.46, so the equation is: q (heat transfered) = 2.46 x 305 x 72 (spec. heat x mass x temp. change.) The answer is 54000 joules, or 54 kilojoules.

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βˆ™ 8y ago
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βˆ™ 8y ago

Specific heat for liquid ethanol is 2.46 J/g/deg.
q = mC∆T = (305g)(2.46 J/g/deg)(72 deg) = 54,022 J = 54 kJ (2 sig figs)

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βˆ™ 8y ago

The answer is 54 kJ.

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Q: How many kilojoules are needed to raise the temperature of 305 g of ethanol from 25 degrees C to 97 degrees C?
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