I can see that the best answer has already been given (the units aren't even remotely close). But suppose that what the asker meant was 125 kVA? In that case, it can be answered.
VA (or Volt-Amperes) is what's used to represent current consumption when the circuit runs on any form of alternating current (AC). Watts (W) don't apply, because of the inherent properties of a changing waveform. To properly calculate the actual put-into-use (or effective) power, one would have to take the entire circuit into account.
But, to answer the speculated question, I would say - anywhere between 125 kW and 0 kW, depending if the load is purely resistive, or purely capacitive in nature, respectively.
(this answer provided for the benefit of Google click-throughs, mostly)
The two values are different. One is voltage and the other is the product of amperage times voltage. The basic equation that involves both values is Watts = Amperage x Voltage. Without an amperage value stated an answer can not be given.
There are zero kW in 125 KV. Watts are the product of amps times volts. Without the amperage given the wattage can not be calculated.
kV is kilovolts, kW is kilowatts, kVA is kilovolt amps and kVAR is kilovolt-amps reactive. A common formula is kVA-squared = kW-squared + kVAR-squared.
Ground clearance132 kv - 6100 mm220 kv - 7015mm400 kv - 8840mm765 kv - 15000mm
1 kw = 0.001 mw 25 kw = 0.025 mw
KV DRDO is located in C.V.Raman Nagar, Bangalore
The standard voltage for transmission is about 115 to 1,200 kV (long-distance transmission). The extreme high voltages are measured more than 2,000 kV and it is exists between conductor and ground.Answer for UKThe standard transmission voltages in the UK are 400 kV and 275 kV. Primary distribution voltages are 132 kV and 33 kV, and secondary distribution voltages are 11 kV and 400 V. These are all line voltages -i.e. voltages measured between line conductors.
Considering it is kw for kilowatt and not kv. 1 megawatt = 1000 kilowatt.
Multiply by Amps.
125 kW is about 167.6 hp
"kV" is referring to voltage, "KW" is referring to power. This is synonomous with asking "how many apples are in the tree?" without giving any more information about the tree, or back to your question, the current.
the average home including 5 computers, washing machine, hair dryer... etc.( dishwasher is not included) uses approximately 25 kW/day
With a dc system the kW are always equal to the kV times the amps. It's only with ac that the kW are usually less than the kVA by a factor called the power factor.
kV measures the voltage, while the kW measures the power. Apart from a general relationship that high power is usually associated with high voltage, nothing more definite can be said.
kV is kilovolts, kW is kilowatts, kVA is kilovolt amps and kVAR is kilovolt-amps reactive. A common formula is kVA-squared = kW-squared + kVAR-squared.
6500 kW at 240 v would need 6,500,000/240 amps, in other words 27,000 amps. That is not practicable. This amount of power would need to be supplied at a much higher voltage, e.g. 11 kV or 33 kV, 3-phase.
There are 0.001 KV in one V.
A lower-case 'k' is used in SI to represent 'kilo' (103).You will see used in symbols such as kW (kilowatts), kV (kilovolts), etc.
1kva means 1kv per ampere therefore 1 amp flowing and 1 kv deduce to be the product of the two or 1kw