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To calculate the power required for a radiographic exposure at 76 kV and 500 mA, you can use the formula: Power (P) = Voltage (V) × Current (I). Here, P = 76 kV × 500 mA = 76,000 volts × 0.5 amps = 38,000 watts, or 38 kW. Therefore, the power required for the radiographic exposure is 38 kW.

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8mo ago

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