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If 1,1 is grams the molarity is 0,317.
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Lithium fluoride has a solubility in water of 0.27 grams per 100 milliliters at 18 degrees Celsius. Its solubility drops to 0.134 grams at 25 degrees Celsius.Ê
It is not a change at all. 79 grams of lithium is a quantity of a substance.
Answer=408.47 250Li2SO4/109.89Li2SO4/2x4x89.774 4LiNO3
The formula for lithium bromide is LiBr. The compound has a molar mass of 86.845 grams per mole. One of its main uses is as a desiccant.
.004
From the definition of molarity, one liter of the stated solution contains 0.256 mole of sodium bromide. The gram formula weight of sodium bromide is 102.89; therefore, one liter of the solution contains 0.256 X 102.89 or 26.34 grams. 18.7/26.34 = 0.710, the fraction of a liter that contains 18.7 grams of sodium bromide.
If 1,1 is grams the molarity is 0,317.
M=#mol solute / Liter of solution #mol solute= mass / molar mass #mol solute= 100 / 87 = 1.15 4= 1.15 / L solution 1.15 / 4 = 0.28 _____________________________________________________________ Since we were only given the (M) and grams of LiBr we had to find the mol of solute. To find the #mol of solute we divided the grams (which were given) over the molar mass of LiBr (87). We then got 1.15 . Now we are able to find the Liter of solution . First we plugged in our given values M= 4 & #mol solute= 1.15 . To find liter of solution we simply dived 1.15 over 4 which equals 0.28. --------------- I suppose that lithium bromide is not so soluble to prepare 4 M solutions in water at 20 0C.
1.3M
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Need moles sodium bromide first. 18.7 grams NaBr (1 mole NaBr/102.89 grams) = 0.1817 moles NaBr =====================Now, Molarity = moles of solute/Liters of solution 0.256 M NaBr = 0.1817 moles NaBr/X Liters Liters = 0.1817/0.256 = 0.7098 Liters -------------------------( you do sigi figis )
Don't try this at home, since Li2S can react very violently with water (much like lithium or sodium metal in water).
No, a AA lithium battery has about 0.75 grams of Lithium.
1.2 Kilograms Calcium bromide (1000 grams/1 kilogram)(1 mole CaBr2/199.88 grams) = 6.0 moles calcium bromide
Because you have 6.68 moles of Li2SO4 and 2.500 liters of water, the overall molarity of your solution is 2.67 M.