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The Si has no lone pairs, but each F has 6 lone pairs. Thus 6 x 4 = 24 lone pairs, total.
3 bond pairs and no lone pairs
8
1
Three bonds and no lone pairs.
two bonds and eight lone pairs
None.
32
26
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The Compound XeF4 has 4 sigma bonds
4 bond pairs (F-N=N-F) plus 3 lone pairs on each fluorine and 1 on each nitrogen:together 8 lone pairs plus 4 bond pairs in both cis- and trans-Dinitrogen difluoride
15 sigma 3 pi 10 lone pairs
It can only make three bonds. Boron has three valence electrons and therefore cannot form more than three bonds with no lone pairs.
The Si has no lone pairs, but each F has 6 lone pairs. Thus 6 x 4 = 24 lone pairs, total.
3 Lone pairs and one unpaired electron