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There are four electrons, which is two pair.
These pairs of electrons are referred to as lone pairs.
There are 2 lone pairs in each Oxygen atom. So there are 4 lone pairs in total, which means 8 lone pair electrons.
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In a water molecule, there are two lone pairs of electrons connected to the oxygen. The lone pairs push the hydrogen atoms, creating a bent shape. In CO2, however, there are two double bonds and no lone electrons on the central atom, hence the molecule has a linear shape.
There are four electrons, which is two pair.
lone pairs
They share two pairs of electrons and have 2 lone pairs
These pairs of electrons are referred to as lone pairs.
There are a total of eight. Two pairs are bond pairs and two are lone pairs.
There are 2 lone pairs in each Oxygen atom. So there are 4 lone pairs in total, which means 8 lone pair electrons.
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Lone-pair electrons, Bonded pairs of electrons
In a water molecule, there are two lone pairs of electrons connected to the oxygen. The lone pairs push the hydrogen atoms, creating a bent shape. In CO2, however, there are two double bonds and no lone electrons on the central atom, hence the molecule has a linear shape.
Lewis dot diagrams represent the bonds between the atoms of a molecule, as well as any lone pair of electrons. For instance, in the O2 molecule, there is a double bond between the two oxygen atoms, but there are also two lone pairs of electrons per oxygen atom.
Lewis dot diagrams represent the bonds between the atoms of a molecule, as well as any lone pair of electrons. For instance, in the O2 molecule, there is a double bond between the two oxygen atoms, but there are also two lone pairs of electrons per oxygen atom.
The answer is not 6 as said here before! The number of valence electrons in O2 (oxygen molecule) is: 12 valence electrons. 6 of them from each oxygen (O) atom. 4 valence electrons make up the double bond between the two oxygen atoms, and the remaining 8 valence electrons form lone pairs (non-bonding pairs) on the oxygen atoms, 2 lone pairs on each. I hope there is some help in this.