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How many memory locations are required to execute rotate accumulator right and rotate accumulator left?
Wiki User
∙ 12y ago
The RAR and RAL instructions require one byte to specify, and four T-cycles to execute, on the 8085.
Wiki User
∙ 12y ago
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What is the difference between load and store instruction?
Load instruction means to load the instruction from the memory to the processor (accumulator).. But store instruction is opposite of it,it stores information from accumulator to the memory.
What program can execute in any area of the memory?
Virtual Memory
What is STA in 8085?
STA is used to store the content of the accumulator in to the specified memory address. for example STA 4200. it stores the content of accumulator at 4200.
How many nuMBer of address lines required for 8 MB of memory?
It takes 23 address lines to address 8 mb of memory.
What is the difference between LDA and STA instructions?
In the 8085, the LDA instruction loads the accumulator from memory, while the STA instructionstores the accumulator to memory. LDA is a read, while STA is a write. LDA is opcode 3AH, while STA is opcode 32H.
Basic steps used by the processor in instruction processing are?
1.Fetch the most instructions from memory. 2.Read an apparend if required by the instruction.(Apparend is a quantity to be operated as directed by its associated instruction.) 3.Execute the instruction.(Do what the instruction says.) 4.Write the result backe into memory.(If required by instruction.)
Once in memory the computer can carry out or the instructions in a program?
execute
How many register in 2K memory chip?
Registers represent the number of memory locations. A 2K memory chip has 2x1024=2048 memory locations. Hence there are 2048 registers in a 2K memory.
How many memory locations can be specified by an 14 - bit address?
A 14 bit address can specify 214 or 16,384 different locations.
Difference between LDA and STA instruction in 8085?
In the 8085, the LDA instruction loads the accumulator from memory, while the STA instruction stores the accumulator to memory. LDA is a read, while STA is a write. LDA is opcode 3AH, while STA is opcode 32H.
How 8085 timing diagram works based on each instruction?
Each instruction requires specific time for the execution of instruction and this time is called instruction cycle. Each instruction cycle consists 1 to 5 machine cycle -- opcode fetch, memory read, memory write, IO read, IO write and each machine cycle consist 3 to 6 T - states. Time required to execute 1 T-state = 1/ operating frequency of 8085 Microprocessor for example operating frequency = 2MHz then time required to execute 1 T-state = 0.5 uSec example: Calculate time required to execute instruction MOV C, A sol: This instruction has one machine cycle i.e. opcode fetch (In any instruction 1st cycle is always opcode fetch and opcode fetch consists 4 to 6 T state depend on the operation of particular instruction) so to execute MOV C, A required 4T states so time required to execute this instruction is 4*0.5usec = 2usec any other queries pls contect: nileshbahadure2000@yahoo.co.in example:Calculate the time required to execute LXI H,2000H sol:Here we have to draw opcode fetch and two memory reads as two bytes 00H and 20H have to be read from memory. i.e, opcode fetch+Memory reads *2(bytes address) =4+3+3 so to execute LXI H,2000H,the required T-states is 10T and time is 10*0.5usec=5usec
How many different memory locations can the HCS12 access with out the expanded memory?
2^16 locations or 65,536 bytes
