MaVa=MbVb
(6.0M NaOH)(x)=(0.10M solution)(1.0L)
x=0.017L of 6.0M NaOH
Convert to mL (1000mL in 1L)
17mL of 6.0M NaOH
The answer is 15 mL. solution 0,2 M NaOH.
no-AH
Simple equality will do here as you have three things and require a fourth. (X L)(2.5 M NaOH) = (2.0 L)(0.75 M NaOH) 2.5X = 1.5 X = 0.60 Liters needed ================
40 grams, this is the 1M NaOH standard laboratory solution.
The NaOH is sodium hydroxide, which is a strong base. The mM seems to be a garbled term. Possibly you are thinking of ml, milliliters.
to prepare 1N we have to dilute 40gms of NaOH in 1 litre of water as for NaOH normality =molarity so to prepare 0.1N NaOH we have to dilute 4gms of NaOH in 1 litre of water..
To prepare the phenoxide, dissolve 23.5 grams of Csl-IsOl-I in 875 milliliters of toluene. On a separate dish, dissolve 10 grams of NaOH in 150 milliliters of methyl alcohol. Pour the solution into a flask and mix.
no-AH
Take 60 gm NaOH (100%) disolve it in distilled water, and make up to 2.0 liter by distlilled water.the prepared solution is 0.75 N NaoH Solution.
Simple equality will do here as you have three things and require a fourth. (X L)(2.5 M NaOH) = (2.0 L)(0.75 M NaOH) 2.5X = 1.5 X = 0.60 Liters needed ================
40 grams, this is the 1M NaOH standard laboratory solution.
The NaOH is sodium hydroxide, which is a strong base. The mM seems to be a garbled term. Possibly you are thinking of ml, milliliters.
to prepare 1N we have to dilute 40gms of NaOH in 1 litre of water as for NaOH normality =molarity so to prepare 0.1N NaOH we have to dilute 4gms of NaOH in 1 litre of water..
we need 0.8gm NaoH and dissolved in 10 ml of water to make 2N solution of NaoH .
One liter of a one molar solution of NaOH in water contains 40g of NaOH. The quantity must be known.
Concentration of NaOH = 0.025 M = 0.025 Moles per Litre of SolutionVolume of Solution required = 5.00LWe can say therefore that:Number of Moles of NaOH needed to prepare the solution= Concentration of NaOH * Volume of Solution requiredTherefore:Number of Moles of NaOH needed to prepare the solution= 0.025M * 5.00L= 0.125molesFrom this we can say that 0.125 moles of NaOH are needed to prepare a 5.00 L solution with a concentration of 0.025M of NaOH.
There is 0.5 moles of NaOH per litre To calculate 0.5 molar NaOH first know the molecular weight of NaOH i.e 40 now multiply the number of moles of NaOH you have (0.5) found as above. so to find the number of grams of NaOH we needed to start with (0.5) * (40) = 20g So dissolve 20g of NaOH in one litre of the solution to prepare 0.5 molar solution
"Dilute NaOH" without any other specifications in a chemistry lab generally refers to a 6M solution of NaOH in water.