Best Answer

There is 0.5 moles of NaOH per litre To calculate 0.5 molar NaOH first know the molecular weight of NaOH i.e 40 now multiply the number of moles of NaOH you have (0.5) found as above. so to find the number of grams of NaOH we needed to start with (0.5) * (40) = 20g So dissolve 20g of NaOH in one litre of the solution to prepare 0.5 molar solution

Study guides

☆☆

More answers

Molar mass of NaOH is roughly 40 g/mol. That is solution is 1N NaOH when 40g NaOH is dissolved in 1L water. Here, molarity and normality will be same.

For our purpose, weigh 20g of NaOH and dissolve it in 500ml water. At this point, the solution is 1N NaOH. Dilute this solution to 1000ml. Stir well. You have 0.5N NaOH solution. Done.

50 mM NaOH solution means that there are .050 moles of NaOH for each liter or solution. Likewise for 5 M meaning 5 moles per liter. So,

5 moles/liter * 1 liter = 5 moles.

So you have 5 total moles of NaOH. You want to use that to make a 50 mM solution.

In order to dilute 5 moles/liter down to .050 moles/liter, you have to add water.

For example, if you only want 1 liter of the final .050 M solution, then you only need .050 moles of NaOH.

So you take the 5M solution and find out how much contains .050 moles of NaOH.

5 moles/liter * x liters = .050 Moles

.050 Moles / 5 moles/liter = .01 liters.

So .01 Liters, or 10 milliliters of the 5 M solution, combined with 990 milliliters of water makes 1 liter of .050 M solution.

The molarity is figured out by the number of moles of NaOH over the number of liters of water. so if the molarity is 0.5M and there is 1.0L of water then there has to be 0.5 moles of NaOH in the solution.

Mol.wt of NAOH= 40

Molarity= amount of solute in g/l of solution/ molw.t

0.5M= g/L / 40

g/l = 0.5 * 40

= 20g

1ml contains 20 g per 1000 ml so

50ml contains= 20/1000* 50 =1g

Typically, this problem means 5% mass/volume which is 5 g NaOH/100 ml solution. This translates into 5 g x 1 mole/40 g = 0.125 moles NaOH/100 ml = 0.125/0.1 L = 1.25 M

If the problem is actually 5 percent mass/mass NaOH, then you have 5 g NaOH/100 g solution. If the masses are additive, that means 95 g H2O (or 95 ml H2O if the density is 1 g/ml). If these assumptions are correct, then you have 5 g NaOH/95 ml H2O. 5 g NaOH x 1 mol/40 g = 0.125 moles NaOH

0.125 moles/0.095 L = 1.32 M

C1 x V1 = C2 x V2 (concentration1)(volume1) = (concentration2)(volume2)

15M(V1) = 5M(V2)

Since you aren't given a volume, its a 3-fold dilution

O (Oxygen) has a molar mass of 16.00g. Na (Sodium) has a molar mass of 22.99g. H (Hydrogen) has a molar mass of 1.01g.

Therefore the molar mass of NaOH (Sodium Hydroxide) is 40.00g.

It depends on how much water you're using.

Since NaOH has a molar mass of 40g/mol, you would use 20 grams of NaOH for every liter of water.

The molar mass of NaOH is 40 g/mole0.5 millimolar (mM) is 0.5 millimoles/liter

To make 1 liter of 0.5 mM you need 0.5 mmol/L x 40 mg/mmole = 20 mg in 1 liter of solution

Q: How do you prepare 0.5 N NaOH solution?

Write your answer...

Submit

Still have questions?

Continue Learning about Chemistry

In order to make 0.02 N NaOH from 0.2 N NaOH, one needs to dilute it by 10 x (10 fold). Depending on the volume of 0.02 N NaOH needed, that will determine the volume of 0.2 N used. For example, to make 100 ml of 0.02 N NaOH, you would dilute 10 mls of 0.2 N to 100 ml. This is seen in the following calculation: (x ml)(0.2 N NaOH) = (100 ml) (0.02 N NaOH) and x = 10 ml

mehedi hasan

Since "normality" is defined as the gram equivalent weight of a substance in a liter of solution, a 0.02 N NaOH solution would have 0.02 gram equivalents of NaOH per liter. To reduce it to 0.01 N you need only dilute it to one half of the original - e.g. 500 ml of NaOH mixed with 500 ml of pure water. Because there is a small change in the density upon mixing, the exact amount of water will differ slightly from 500 ml, but for a solution as dilute as 0.02 N, it won't be that far off. The best way to get it exact would be to start with a known volume of 0.02 N NaOH and then add enough water to bring the total to exactly twice the original volume. This might be accomplished by doing it in a graduated cylinder or adding it from a burette into a volumetric flask. the important thing is to know the starting volume of the 0.02 N solution and the final volume of the diluted (0.01 N) solution

Hi, 6N NaOH = 6M NaOH 6M NaOH are 6 moles in 1L Mw (NaOH) = 39.88 gr/mole so: m = n x MW = 6 x 39.88 = 239.28 gr NaOH. :)

It is same, instead of water take methanol...

Related questions

Take 60 gm NaOH (100%) disolve it in distilled water, and make up to 2.0 liter by distlilled water.the prepared solution is 0.75 N NaoH Solution.

Dissolve 0.4 g of NaOH in 100 ml of water. Try it out. Actually it is not suitable to prepare NaOH solutions in standard flasks.It should be made in beakers & must be standardised..This is done to find the correct normality...

In order to make 0.02 N NaOH from 0.2 N NaOH, one needs to dilute it by 10 x (10 fold). Depending on the volume of 0.02 N NaOH needed, that will determine the volume of 0.2 N used. For example, to make 100 ml of 0.02 N NaOH, you would dilute 10 mls of 0.2 N to 100 ml. This is seen in the following calculation: (x ml)(0.2 N NaOH) = (100 ml) (0.02 N NaOH) and x = 10 ml

mehedi hasan

Since "normality" is defined as the gram equivalent weight of a substance in a liter of solution, a 0.02 N NaOH solution would have 0.02 gram equivalents of NaOH per liter. To reduce it to 0.01 N you need only dilute it to one half of the original - e.g. 500 ml of NaOH mixed with 500 ml of pure water. Because there is a small change in the density upon mixing, the exact amount of water will differ slightly from 500 ml, but for a solution as dilute as 0.02 N, it won't be that far off. The best way to get it exact would be to start with a known volume of 0.02 N NaOH and then add enough water to bring the total to exactly twice the original volume. This might be accomplished by doing it in a graduated cylinder or adding it from a burette into a volumetric flask. the important thing is to know the starting volume of the 0.02 N solution and the final volume of the diluted (0.01 N) solution

add 10 grams of NaoH into 1000 ml water, it will give you NaoH of 0.25N. As for making 1N solution you need to disolve 40 grams of NaoH into 1 litre water.

Hi, 6N NaOH = 6M NaOH 6M NaOH are 6 moles in 1L Mw (NaOH) = 39.88 gr/mole so: m = n x MW = 6 x 39.88 = 239.28 gr NaOH. :)

It is same, instead of water take methanol...

0.5 N

Take 10ml of 1N NaOH and dilute to 100ml with distilled water or take 0.4g of NaOH pellets and dissolve in 1000L distilled water.

- Weight 0,4 g of NaOH - Transfer the granules in a 1 L volumetric flask - Add 9oo mL distilled water; maintain the flask in a thermostat at 20 0C, for min. half hour - Add distilled water up to the mark - Stir the content To know the correct concentration this solution must be titrated with an acid.

pottassium permangate