0
How many ml of 6.0 N NaOH is required to neutralize 30 ml of 4 N HCL?
Wiki User
∙ 13y ago
formula for neutralizatrion is
volume of acid X normality of acid = volume of base X normality of base
so
(0.3)(3) should equal (4)(volume)
which is .225L.
However, Ca(OH)2 contains 2 moles of OH resulting division of total volume needed by 2.
Thus, the answer becomes .1125L or 112.5ml.
Wiki User
∙ 14y ago
Wiki User
∙ 13y ago1 mole of NaOH will neutralize 1 mole of HCl.
How many moles of HCl do you have in 30 ml of 4 N HCl? Well, 1 L * 1 N = 1 mol.
So, 30 ml = 0.03 L. 0.03 L * 4 N = 0.12 mol HCl. That means you will need 0.12 mol NaOH to neutralize your HCl.
Now, how many mL of 6.0 N NaOH will give us 0.12 mol NaOH? 0.12 mol / 6 N = 0.02 L NaOH = 20 mL.
Thus, you will need 20 mL 6.0 N NaOH to neutralize 30 mL of 4 N HCl.
Add your answer:
Earn +20 pts
When just enough acid has been added to neutralize the sodium hydroxide what will the pH be?
When just enough strong acid (e.g. HCl) is used to neutralize a strong base (NaOH), the pH should be neutral (pH = 7.0).
What is the concentration of 300.0 mL of an HCl solution that required 16.4 mL of 6.90 M NaOH to neutralize?
The answer would be theoretically , 16.4* 6.9/300=0.3772M But one thing this concentration of NaOH is pretty high, and is not practical to make this solution. Concentration 6.9M means that you'll have to dissolve 40*6.9=286gm NaOH in one 1 litre water. Thus more than 4 gm are present in that 16.4 ml, which is very difficult.
Which two compounds are electrolytes?
NaOH and HCl
What are the functions of NaOH in benzoylation of amine?
in benzoylation of amine, HCl is produced which by adding NaOH, HCl consumed and the raction proceed for production of further benzoylation product.
How many moles of NaCl are formed from the reaction between 1.4 moles of HCl and 2.8 moles NaOH?
1.4 moles - the HCl is the limiting ingredient
How many ml of 250 M NaOH are required to neutralize 30.4 ml of 152 M HCl?
To neutralize the acid, we need to use the same number of moles of base. First, calculate the number of moles of HCl using its concentration and volume. Then, use the mole ratio from the balanced equation to find the required volume of NaOH. Convert the volume to mL.
How many milliliters of 0.400 M NaOH are required to completely neutralize 20.00 mL of 0.200 M HCl?
To neutralize HCl with NaOH, the mole ratio is 1:1. So, the moles of HCl are 0.200 M x 0.020 L = 0.004 moles. Since NaOH and HCl react in a 1:1 ratio, we need 0.004 moles of NaOH. Using the molarity formula, we find that we need 0.010 L or 10.00 mL of 0.400 M NaOH.
What volume in mL of a 1.06 M NaOH solution is required to neutralize 11 g of HCl?
First, calculate the number of moles of HCl using the molar mass. Then, determine the number of moles of NaOH needed to neutralize the HCl based on the 1:1 stoichiometry of the reaction. Finally, use the molarity of NaOH to find the volume required using the formula Molarity = moles/volume.
How many moles of NaOH will it take to neutralize 0.61 L of 0.46 M HCl?
1st Get the balanced equation NaOH + HCl -> NaCl + H2O Find the number of moles in HCl; n = cv n = 0.46x0.61 n = 0.2806 moles the number of moles of HCl and NaOH is the same so 0.2806moles will be needed
Formula for NaOH and HCl?
The chemical formula for sodium hydroxide is NaOH, while the chemical formula for hydrochloric acid is HCl.
How many ml of 0.43 m naoh will be needed to neutralize 10 ml of stomach acid if stomach acid is 0.1 m hcl?
Balanced equation first.NaOH + HCl -> NaCl + H2OAll one to one so a simple equality will do here.(X ml)(0.43 M NaOH) = (10 ml)(0.1 M HCl)0.43X = 1X = 2.3 milliliters NaOH needed--------------------------------------
What volume of 0.200 m hcl is required to completely neutralize 20.00 0f 0.300 m koh?
30 mL of HCl
How many grams of sodium hydroxide will react with 73.00 g of aqueous HCl?
The balanced chemical equation for the reaction between sodium hydroxide (NaOH) and hydrochloric acid (HCl) is 1 mol NaOH : 1 mol HCl. Calculate the amount of NaOH required by converting the given mass of HCl to moles using its molar mass, then use the mole ratio from the balanced equation to determine the moles of NaOH needed, and finally convert moles of NaOH to grams using its molar mass.
How much caustic soda is required to neutralize a 25ml HCl solution at pH 3?
One step at a time.1/103 = 0.001 M HCl, so.....Molarity = moles of solute/Liters of solution ( 25 ml = 0.025 Liters )0.001 M HCl = X moles HCl/0.025 Liters= 2.5 X 10 - 5 moles HCl========================now, balanced eqiationNaOH + HCl --> NaCl + H2O ( all one to one )( now drive reaction towards mass NaOH )2.5 X 10 - 5 moles HCl (1 moles NaOH/1 mole HCl)(39.998 grams/1 mole NaOH)= 10 -4 grams caustic soda needed==========================
When just enough acid has been added to neutralize the sodium hydroxide what will the pH be?
When just enough strong acid (e.g. HCl) is used to neutralize a strong base (NaOH), the pH should be neutral (pH = 7.0).
What do you call a process where an acid and a base neutralize one another?
The process where an acid and a base neutralize each other are called neutralization reaction. The products of this process are a salt and water. For example:- NaOH + HCl -------> NaCl + H2O
What is HCl NaOH H2O is it Salt?
The compound HCl NaOH H2O is a mixture of hydrochloric acid (HCl) and sodium hydroxide (NaOH) in water (H2O). When mixed, HCl and NaOH neutralize each other to produce water and salt - in this case, sodium chloride (NaCl). So, technically, it is not a salt but a mixture that can produce salt under certain conditions.
