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How many grams of H2O would you need to obtain 32.9g of O2?
32.9 g / 32.0 (g/molO2) = 1.028 mol O21.028 (O2) * 2 (H2O) * 18.02 (g/mol ) = 37.1 gram H2O
How many liters of water can be made from 5 L of oxygen gas and an excess of hydrogen?
55 grams O2 × (1 mol O2 ÷ 32 g O2) × (2 mol H2O ÷ 1 mol O2) × (22.4 L ÷ 1 mol H2O) = 77 L H2O(g)In the liquid form, it works out to just under 62 milliliters.
How many moles of H2O are produced when 0.468 mol of octane is burned?
It forms H2O when burned.There are 3.744 moles of H2O after burned.
The number of moles of h2o formed when 1 mole of o2 reacts with c5h12 in the reaction c5h12 plus 8o2 equals 5co2 plus 6h2o is?
C5H12 + 8 O2 --> 5 CO2 + 6 H2O (1 mol O2)(6 mol H2O/8 mol O2) = 0.75 mol H2O
How many gram of water is equal to 2.2 mol of water?
2.2 mol water = 2.2 (mol) * 18 (g/mol) water = 39.6 (mol*g/mol) = 40 g18 g/mol = mol mass of H2O = 2*H + 1*O = (2*1 + 16) g/mol
How many mol of H are in 4.51 mol H2O?
4,51 moles hydrogen exist.
How many molecules of H2O are in 0.583 mol of H2O?
1.08x10^22
How many moles are in 8g of H2O?
8g / 18 g/mol H2O = .44 moles H2O
How many grams of water are produced by reacting 15.8 g H2 with excess oxygen?
24g H2 x 1 mol H2 x 2 mol H2O x 18g H2O/ 2g H2 x 2 mol H20= 216 g H2O 160g O2 x 1 mol O2 x 2 mol H2O x 18g H2O/ 32g O2 x 1 mol O2 x 1 mol H2O= 180 g H2O
How many moles are of H2O are needed to react completely with 7.54 mol of K?
7.54 mol of K
How many grams of copper sulfate would you heat to produce 29.8g of water?
29.8g H2O = 1.66 mol H2O Molar Mass CuSO4 * 5H2O = 249.6 g mol CuSO4 * 5H2O --> 5 mol H2O 249.6 g CuSO4 * 5H2O/1 mol CuSO4 * 5H2O Times * 1mol CuSO4 * 5H2O/5mol H2O Times* 1.66 mol H2O = 82.6 g CuSO4 * 5H2O
When 0.600 mol Mg3N2 reacts with 4.00 mol H2O what is the limiting reactant?
H2o
How many grams of copper sulfate pentahydrate CuSO4 5H2O would you heat to produce 29.8 g of water?
29.8g H2O = 1.66 mol H2O Molar Mass CuSO4 * 5H2O = 249.6 g mol CuSO4 * 5H2O --> 5 mol H2O 249.6 g CuSO4 * 5H2O/1 mol CuSO4 * 5H2O Times * 1mol CuSO4 * 5H2O/5mol H2O Times* 1.66 mol H2O = 82.6 g CuSO4 * 5H2O
How many molecules are in 0.357 mol of water?
1 mole H2O = 6.022 x 1023 molecules 0.357mol H2O x 6.022 x 1023 molecules/mol = 2.15 x 1023 molecules H2O
How many grams of H2O would you need to obtain 32.9g of O2?
32.9 g / 32.0 (g/molO2) = 1.028 mol O21.028 (O2) * 2 (H2O) * 18.02 (g/mol ) = 37.1 gram H2O
The mass percent of water in a hydrate of mncl2 is 36.41 percent what is the fomular of the hydrate?
36.41% = .3641 g of H2O 63.59% = .6359 g of MnCl2 .6359g MnCl2 x (1molm MnCl2/125.84g MnCl2)=.0051 mol MnCl2 .3641g H2O x (1 mol H2O/ 18.02g H2O) = .0202 mol H2O .0051 mol MnCl2 / .0051 = 1mol MnCl2 .0202 mol H2O /.0051 = 3.96 = 4 mol H2O Formula is: MnCl2 4H2O Manganese (II) chloride tetrahydrate
How many molecules are in 6.9 g H2O?
The number of molecules is 2,308.10e23.
