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55 grams O2 × (1 mol O2 ÷ 32 g O2) × (2 mol H2O ÷ 1 mol O2) × (22.4 L ÷ 1 mol H2O) = 77 L H2O(g)

In the liquid form, it works out to just under 62 milliliters.

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Q: How many liters of water can be made from 5 L of oxygen gas and an excess of hydrogen?
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