The number of molecules is 12,044280.10e23.
0.2 moles C6H12O6 x 6.02x10^23 molecules/mole = 1.2x10^23 molecules of C6H12)61.2x10^23 molecules C6H12O6 x 6 molecules "O"/molecule C6H12O6 = 7.2x19^23 molecules "O"
There are 0.13 moles in 20 grams of magnesium nitrate.
No, this would make 5 moles. This is because water is H2O. This means that for each oxygen molecule used, there will be 2 hydrogen molecules used. In the given equation Only 5 moles of oxygen could be used to pair with all 10 moles of hydrogen, therefore giving you an excess of 5 oxygen molecules.
To find moles, simply divide the number of representative particles (in this case, molecules of methane) by Avogadro's number (6.02x1023.)2.45x1023/6.02x1023 = approx. 0.41 moles (the exponents cancel out.)
The answer is 1,83 moles.
NH3 Molecules = ( 8.1 x 10^20 H atoms ) ( 1 NH3 molecule / 3 H atoms ) NH3 Molecules = 2.7 x 10^20 NH3 molecules NH3 moles = ( NH3 molecules ) / ( N Avogadro ) NH3 moles = ( 2.7 x 10^20 NH3 molecules ) / ( 6.022 x 10^23 molecules / mole ) NH3 moles = 4.48 x 10^-4 NH3 moles <--------------
20 moles
0.2 moles C6H12O6 x 6.02x10^23 molecules/mole = 1.2x10^23 molecules of C6H12)61.2x10^23 molecules C6H12O6 x 6 molecules "O"/molecule C6H12O6 = 7.2x19^23 molecules "O"
20 moles of NaOH needed to neutralize 20 moles of nitric acid
There are 0.13 moles in 20 grams of magnesium nitrate.
One "mole" of any substance is "Avogadro's number", of these atoms or molecules. Avogadro's Number is 6.023*10e23, or 6023 followed by another 20 zeroes. So 6.10 moles of sulfur is 6.1 * 6.023*10e23.
No, this would make 5 moles. This is because water is H2O. This means that for each oxygen molecule used, there will be 2 hydrogen molecules used. In the given equation Only 5 moles of oxygen could be used to pair with all 10 moles of hydrogen, therefore giving you an excess of 5 oxygen molecules.
40 moles of LiOH
To find moles, simply divide the number of representative particles (in this case, molecules of methane) by Avogadro's number (6.02x1023.)2.45x1023/6.02x1023 = approx. 0.41 moles (the exponents cancel out.)
Molarity = moles of solute/Liters of solution Or, for our purposes, Moles of solute = Liters of solution * Molarity Moles Na2CO3 = 10.0 Liters * 2.0 M = 20 moles Na2CO3 --------------------------
20
The answer is 1,83 moles.