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How many moles are in 400 grams of nickel sulphate?
400 grams of nickel sulphate (anhydrous) is equivalent to 2,58 moles.
How many moles are there in 400g of calcium cabonate?
400 g of calcium cabonate is equal to 3,996 moles.
How many carbon dioxide molecules are produced in one particle?
I think there are 400 carbon molecules
What volume is needed to store 0.050 moles of helium gas at 202.6 kPa and 400 K?
The volume is 0,82 L.
300.0 Ml of water is added to .40 L of a .400 M Na2CrO4 solution what is the molarity of the resulting solution?
300.0 ml of water is added to .40 L of a .400 M Na2CrO4 solution what is the molarity of the resulting solution? Na2CrO4 = 2 Cr +Cr + 4 O's Molar mass = (2*23 + 52 + (4*16) = 162 A .400 M N Na2CrO4 solution has .400 moles of Na2CrO4 in a liter of water. .400 moles of Na2CrO4 = 0.400 * 162 = 64.8 grams of Na2CrO4 in a liter of water. Since you only have .40 L, you have 64.8 grams/liter * 0.4L = 25.92 grams of Na2CrO4 in 0.4 liter of solution. When you add 300.0 ml of water, you have total of 700 ml of solution. You still have 25.92 grams of Na2CrO4, but now you have 700 ml of solution. Molarity = moles of solute per liter of solution. Moles of solute = grams of solute ÷ Molar mass of solute Moles of solute = 25.92 ÷ 162 = 0.16 moles of Na2CrO4. Molarity = 0.16 moles of Na2CrO4 ÷ 0.700 L of solution. Molarity = 0.23 M
How many moles are in 400 grams of nickel sulphate?
400 grams of nickel sulphate (anhydrous) is equivalent to 2,58 moles.
How many moles of sodium chloride are in 400 mL of a 6 M NaCl solution?
The answer is 2,4 moles.
How many moles are there in 400g of calcium cabonate?
400 g of calcium cabonate is equal to 3,996 moles.
What is the final concentration if 75.0 mL of a 3.50 M glucose solution is diluted to a volume of 400 mL?
A 1 mole glucose solution means that there would be 1 mol/liter. There is only .075 liters, so there is only .075 moles present. .075 moles in 400 milliliters is a .075 to .4 ratio. By expanding the ratio, it is found that there are .1875 moles to 1 liter, making the final concentration 0.1875 M.
How many carbon dioxide molecules are produced in one particle?
I think there are 400 carbon molecules
What is the number of moles of solute in 400 ml of a 0.4 M solute?
The answer is 0,16 moles.
Suppose you have 20.8 g of Cr What number of moles of Cr is present?
.400 moles
How do you calculate the number of moles of NaI in 50.0mL of a 0.400M solution?
First convert mL to liters. So .05L. We know that we have .400 moles/liter, so multiply .05L*.400 mol/L and the L cancels out, leaving us with .02 moles.
How many moles of aluminum oxide are present in a sample having a mass of 178.43g?
For this you need the atomic (molecular) mass of Al2O3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. Al2O3= 102 grams408 grams Al / (102 grams) = 4.00 moles Al
How many grams of solid sodium hydroxide are required to prepare 400 milliliters of a 4 hundredth molar solution?
So you want 0.04M but you have 400ml, not a litre. 0.04/1000*400 is 0.016 moles wanted. 0.016*40 (molecular weight) is 0.64g
What volume is needed to store 0.050 moles of helium gas at 202.6 kPa and 400 K?
The volume is 0,82 L.
300.0 Ml of water is added to .40 L of a .400 M Na2CrO4 solution what is the molarity of the resulting solution?
300.0 ml of water is added to .40 L of a .400 M Na2CrO4 solution what is the molarity of the resulting solution? Na2CrO4 = 2 Cr +Cr + 4 O's Molar mass = (2*23 + 52 + (4*16) = 162 A .400 M N Na2CrO4 solution has .400 moles of Na2CrO4 in a liter of water. .400 moles of Na2CrO4 = 0.400 * 162 = 64.8 grams of Na2CrO4 in a liter of water. Since you only have .40 L, you have 64.8 grams/liter * 0.4L = 25.92 grams of Na2CrO4 in 0.4 liter of solution. When you add 300.0 ml of water, you have total of 700 ml of solution. You still have 25.92 grams of Na2CrO4, but now you have 700 ml of solution. Molarity = moles of solute per liter of solution. Moles of solute = grams of solute ÷ Molar mass of solute Moles of solute = 25.92 ÷ 162 = 0.16 moles of Na2CrO4. Molarity = 0.16 moles of Na2CrO4 ÷ 0.700 L of solution. Molarity = 0.23 M
