There are 6.02x1023 atoms in one mole of any substance. This number is a constant known as Avogadro's number. Check it out on wikipedia here...http://en.wikipedia.org/wiki/Avogadro%27s_number. As far as calculating your answer, just multiply and don't lose track of your decimal places.
Mass V = 76 g moles V = 76/ 51 g/mol=1.5 moles O = 100 - 76/ 16= 1.5 VO Moles V = 68/51 = 1.3 Moles O = 100-68/16=2 1.3/1.3 = 1 =>V 2/1.3=1.5 =>O multiply by 2 to get whole numbers V2O3 moles V = 61/51=1.2 moles O = 100-61/16=2.4 VO2 moles V = 56/51=1.1 moles O= 100-56/16= 2.75 1.1/1.1= 1 => V 2.75/1.1= 2.5 =>O to get whole numbers multiply by 2 V2O5
47 protons, 47 electrons and 61 neutrons
108 - 47 = 61 neutrons 47 = atomic number of silver = number of protons
As silver atoms have 47 protons, the given isotope has 61 neutrons.
There are about 61 neutrons in silver. It actually has less electrons and protons than neutrons, since it only has 47 of them.
The chemical equation is 2Al+3Br2 --> 2AlBr3 So find the number of moles of the aluminum and bromine. Moles of aluminum = 31 g Al/ 27 g/mol = 1.15 moles Moles of bromine = 97.5g/ 159.8 g/mol = .61 moles Then you find the limiting reagent by dividing the number of moles of each substance by their coefficient. 1.15 moles Al / 2 = .575 .61 moles Br / 3 = .203 That means that .203 *2 moles of AlBr3 was produced, because once the Br reactant runs out, the reaction stops and you cannot get anymore of the product. So .406 moles of AlBr3 multiplied by the molecular weight of AlBr3, 266.7 g/mol, yields 108.28 grams of AlBr3
Mass V = 76 g moles V = 76/ 51 g/mol=1.5 moles O = 100 - 76/ 16= 1.5 VO Moles V = 68/51 = 1.3 Moles O = 100-68/16=2 1.3/1.3 = 1 =>V 2/1.3=1.5 =>O multiply by 2 to get whole numbers V2O3 moles V = 61/51=1.2 moles O = 100-61/16=2.4 VO2 moles V = 56/51=1.1 moles O= 100-56/16= 2.75 1.1/1.1= 1 => V 2.75/1.1= 2.5 =>O to get whole numbers multiply by 2 V2O5
61 inches.
There are 61 feet in 61 feet.
61
61 inches = 1.5494 meters.
61 altogether in June and July 31 +30 61
244 ÷ 61 = 4.
61 years = 534,714.6 hours.
61 has 2 sig figs.
305/61 = 5
125 ÷ 61 = 2 with remainder 3.