Assuming a density of 1.0 g/ml for water, then 10 ml H2O = 10 g
10 g H2O x 1 mol/18 g = 0.5555 moles H2O
0.5555 moles x 6.02x10^23 molecules/mole = 3.34x10^23 molecules of H2O in 10 ml
6.022 * 10^23 = 1 mole 3.011 * 10^23 = 1/2 a mole
A 50g sample of H2O contains approximately 2.78 x 10^24 molecules of water. This is calculated by first converting the mass to moles, then using Avogadro's number to determine the number of molecules present in that many moles of water.
12.044*10^23 atoms 1.5055*10^23 S8 molecules
Five molecules of hydrogen have 10 atoms.
20 hydrogen 10 oxygen
Amylase is a catalyst (enzime).Amylose is the polysaccharide.
Each water molecule contains two hydrogen atoms. Therefore, the number of water molecules present in the sample can be calculated by dividing the number of hydrogen atoms by 2. In this case, 3.6 moles of hydrogen atoms corresponds to 1.8 moles of water molecules. This is equal to approximately 1.08 x 10^24 water molecules.
3.345*10^23
There are approximately 1.332×10^24 water molecules in the ocean.
To find this out you simply times 17 by avogadros number 17mol H2O X 6.022x10^23 molecules of anything/mol of anything mols cancel and you are left in molecules of H2O the answer is 1.024x10^25 molecules H2O
A mole of water contains avagadro's number of molecules of water. Therefore 5.65 moles contains 5.65 * 6.022x1023 molecules of water which equals 3.40243x1024 molecules of water.
There are approximately 5.8 x 10^24 molecules in 9.6 mol of C2H4. This is calculated using Avogadro's number, which is 6.022 x 10^23 molecules/mol.