8.3 grams HCl (1 mole HCl/36.458 grams)
= 0.23 moles HCl
------------------------
2 g HCl are equivalent to 0,0548 moles.
Divide by molar mass and check the units(italicalized):0.140 (g HCl) / 36.45 (g.mol-1HCl) = 3.84*10-3 mol HCl
Molarity = moles of solute/Liters of solution ( 50 ml = 0.05 Liters ) 12 M HCl = moles HCl/0.05 Liters = 0.60 moles HCl
Use grams to moles to moles to grams: 0.2 g of ammonia gas (NH3) is equivalent to 0.012 moles of NH3 (divide by 17g/mole) One mole of NH3 reacts with one mole of HCl: NH3 + HCl <=> NH4Cl So we need 0.012 moles of HCl to react with 0.012 moles of NH3 0.012 moles HCl * 36.5 g/mole HCl => 0.43 g HCl
0,0011 moles of hydrogen are obtained.
2 g HCl are equivalent to 0,0548 moles.
67,4 g HCl is equivalent to 1,85 moles.
The answer is 25,522 g.
Divide by molar mass and check the units(italicalized):0.140 (g HCl) / 36.45 (g.mol-1HCl) = 3.84*10-3 mol HCl
Molarity = moles of solute/Liters of solution ( 50 ml = 0.05 Liters ) 12 M HCl = moles HCl/0.05 Liters = 0.60 moles HCl
Use grams to moles to moles to grams: 0.2 g of ammonia gas (NH3) is equivalent to 0.012 moles of NH3 (divide by 17g/mole) One mole of NH3 reacts with one mole of HCl: NH3 + HCl <=> NH4Cl So we need 0.012 moles of HCl to react with 0.012 moles of NH3 0.012 moles HCl * 36.5 g/mole HCl => 0.43 g HCl
0,0011 moles of hydrogen are obtained.
Taking rust to be Fe2O3, you would have the following reaction:Fe2O3 + 6HCl ==> 2FeCl3 + 3H2O100 g Fe2O3 x 1 mole Fe2O3/159.7 g = 0.626 moles Fe2O3moles HCl needed = 0.626 moles Fe2O3 x 6 moles HCl/mole Fe2O3 = 3.76 moles HCl neededMass HCl needed = 3.76 moles HCl x 36.5 g/mole = 137 g HCl needed
Molarity = moles of solute/Liters of solutionSo, get moles HCl.73 grams HCl (1 mole HCl/36.458)= 2.00 moles HCl---------------------------Molarity = 2.00 moles HCl/2 Liters= 1 M HCl=======
1. First, remember definition of M (moles), M = moles of species / L. 0.33 M = 0.33 moles HCl / L 2. Then, multiple your volume by the molar concentration: 0.33 moles HCl / L x 0.70 L = 0.231 moles HCl or you can say n=CONCENTRATION multiply by VOLUME(HCl) which gives 2310 mol HCl It's helpful to carry the units with your calculations. That way you can check that numerators and denominators cancel to give you the units of your answer.
To calculate moles of HCl in 291.68 grams, use the molar mass of HCl which is 1 + 35.5 = 36.5g/mole. 291.68 g x 1 mol/36.5 g = 7.99 moles HCl (3 sig figs)
Well HCl is 36.5 molecular weight so if you have 65 g you would have 65/36.5 moles = 1.78 moles to 2 decimal places