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1 mole of HCl is 36.5g so 0.25 moles are 36.5 x 0.25 = 9.125g
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∙ 14y ago
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How many moles HCl in 8.3 g HCl?
8.3 grams HCl (1 mole HCl/36.458 grams) = 0.23 moles HCl ------------------------
How many moles are in 2 grams of HCL?
2 g HCl are equivalent to 0,0548 moles.
How many moles of HCl are on 10 grams of substance?
The answer is 0,274 moles.
How many moles of HCL are there in 108 grams of the substance?
The answer is: 2,96 moles.
How many grams of HCl are needed to obtain 1.0 liter of a 0.22 M HCl solution?
First.Molarity = moles of solute/Liters of solution0.22 M HCl = X moles/1.0 L= 0.22 moles HCl--------------------------Second.0.22 moles HCl (36.458 grams/1 mole HCl)= 8.0 grams hydrochloric acid needed===========================
How many moles HCl in 8.3 g HCl?
8.3 grams HCl (1 mole HCl/36.458 grams) = 0.23 moles HCl ------------------------
How many moles are in 2 grams of HCL?
2 g HCl are equivalent to 0,0548 moles.
How many moles of HCL are there in 108 grams of the substance?
The answer is: 2,96 moles.
How many moles of HCl are on 10 grams of substance?
The answer is 0,274 moles.
How many grams of HCl are needed to obtain 1.0 liter of a 0.22 M HCl solution?
First.Molarity = moles of solute/Liters of solution0.22 M HCl = X moles/1.0 L= 0.22 moles HCl--------------------------Second.0.22 moles HCl (36.458 grams/1 mole HCl)= 8.0 grams hydrochloric acid needed===========================
How many moles of HCL are in 2.5 L of 0.5 M solution ?
1.25 moles HCl
How many grams are 0.7 moles of HCL?
The answer is 25,522 g.
How would you prepare 17.2 L of a 3.8 M HCl solution?
First get moles HCl, then get the grams HCl.Molarity = moles of solute/Liters of solution3.8 M HCl = X moles/17.2 Liters= 65.36 moles HCl===============so,65.36 moles HCl (36.458 grams/1 mole HCl)= 2382.89 grams HCl======================and,put this amount, 2382.89 grams, 65.36 moles HCl into the 17.2 liters of solution ( water, I suppose ) 2382.89 grams = 2.38 kilograms. I suppose you could weigh out the HCl in a flask of some sort.
How many moles of atoms are present in 154 g of HCl?
Divide by molar mass and check the units(italicalized):0.140 (g HCl) / 36.45 (g.mol-1HCl) = 3.84*10-3 mol HCl
How many grams of zinc can react with 225ml of 0.200 m HCl solution?
Balanced equation first.Zn + 2HCl - ZnCl2 + H2now we find moles HCl by....Molarity = moles of solute/Liters of solution ( 225 ml = 0.225 Liters )0.200 M HCl = X moles/0.225 Liters= 0.045 moles HCl================Now, drive reaction backwards.0.045 moles HCl (1 mole Zn/2 mole HCl)(65.41 grams/1 mole Zn)= 1.47 grams zinc reacted----------------------------------
How many moles are in 291.68 grams of hydrochloric acid?
To calculate moles of HCl in 291.68 grams, use the molar mass of HCl which is 1 + 35.5 = 36.5g/mole. 291.68 g x 1 mol/36.5 g = 7.99 moles HCl (3 sig figs)
How many grams of sodium carbonate is needed to react with 18.1 ml of 0.23M HCL?
Balanced equation always first!! Na2CO3 + 2HCl -> 2NaCl + CO2 + H2O Find moles HCl by---Molarity = moles of solute/Liters of solution (18.1 ml = 0.0181 L) 0.23 M HCl = moles HCl/0.0181 liters = 0.004163 moles HCl Drive back against sodium carbonate stoichometrically 0.004163 moles HCl (1 mole Na2CO3/2 mole HCl)(105.99 grams/1 mole Na2CO3) = 0.22 grams Na2CO3 needed --------------------------------------------
