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How many moles HCl in 8.3 g HCl?
8.3 grams HCl (1 mole HCl/36.458 grams) = 0.23 moles HCl ------------------------
How many moles are in 2 grams of HCL?
To find the number of moles in 2 grams of HCl, you need to divide the mass by the molar mass of HCl. The molar mass of HCl is approximately 36.46 g/mol. Therefore, 2 grams of HCl is equal to 2/36.46 = 0.055 moles.
How many moles of HCl are on 10 grams of substance?
To find the number of moles, you need to divide the given mass (10 grams) by the molar mass of HCl (36.46 g/mol). This will give you approximately 0.274 moles of HCl.
How many moles of HCL are there in 108 grams of the substance?
To find the number of moles in 108 grams of HCl, you need to know the molar mass of HCl, which is about 36.5 g/mol. You can then use this molar mass to calculate the number of moles by dividing the given mass by the molar mass. In this case, 108 grams divided by 36.5 g/mol gives you about 2.96 moles of HCl.
How many moles of solute are in 50 mL of a 12 M HCl solution?
To find the number of moles of solute in the solution, first, calculate the amount of HCl in grams using the formula: moles = molarity x volume (in liters). Then, convert the grams of HCl to moles by dividing by the molar mass of HCl (36.46 g/mol).
How many moles HCl in 8.3 g HCl?
8.3 grams HCl (1 mole HCl/36.458 grams) = 0.23 moles HCl ------------------------
How many moles are in 2 grams of HCL?
To find the number of moles in 2 grams of HCl, you need to divide the mass by the molar mass of HCl. The molar mass of HCl is approximately 36.46 g/mol. Therefore, 2 grams of HCl is equal to 2/36.46 = 0.055 moles.
How many moles of HCl are on 10 grams of substance?
To find the number of moles, you need to divide the given mass (10 grams) by the molar mass of HCl (36.46 g/mol). This will give you approximately 0.274 moles of HCl.
How many grams are 0.7 moles of HCL?
The answer is 25,522 g.
How many moles of HCL are there in 108 grams of the substance?
To find the number of moles in 108 grams of HCl, you need to know the molar mass of HCl, which is about 36.5 g/mol. You can then use this molar mass to calculate the number of moles by dividing the given mass by the molar mass. In this case, 108 grams divided by 36.5 g/mol gives you about 2.96 moles of HCl.
How many moles of solute are in 50 mL of a 12 M HCl solution?
To find the number of moles of solute in the solution, first, calculate the amount of HCl in grams using the formula: moles = molarity x volume (in liters). Then, convert the grams of HCl to moles by dividing by the molar mass of HCl (36.46 g/mol).
How many moles are in 291.68 grams of hydrochloric acid?
To calculate moles of HCl in 291.68 grams, use the molar mass of HCl which is 1 + 35.5 = 36.5g/mole. 291.68 g x 1 mol/36.5 g = 7.99 moles HCl (3 sig figs)
How many moles of HCL are in 2.5 L of 0.5 M solution ?
There are 1.25 moles of HCl in 2.5 L of a 0.5 M solution of HCl. This can be calculated by multiplying the volume (2.5 L) by the concentration (0.5 mol/L).
How many grams of zinc can react with 225ml of 0.200 m HCl solution?
Balanced equation first.Zn + 2HCl - ZnCl2 + H2now we find moles HCl by....Molarity = moles of solute/Liters of solution ( 225 ml = 0.225 Liters )0.200 M HCl = X moles/0.225 Liters= 0.045 moles HCl================Now, drive reaction backwards.0.045 moles HCl (1 mole Zn/2 mole HCl)(65.41 grams/1 mole Zn)= 1.47 grams zinc reacted----------------------------------
How would you prepare 17.2 L of a 3.8 M HCl solution?
First get moles HCl, then get the grams HCl.Molarity = moles of solute/Liters of solution3.8 M HCl = X moles/17.2 Liters= 65.36 moles HCl===============so,65.36 moles HCl (36.458 grams/1 mole HCl)= 2382.89 grams HCl======================and,put this amount, 2382.89 grams, 65.36 moles HCl into the 17.2 liters of solution ( water, I suppose ) 2382.89 grams = 2.38 kilograms. I suppose you could weigh out the HCl in a flask of some sort.
How many grams of sodium carbonate is needed to react with 18.1 ml of 0.23M HCL?
Balanced equation always first!! Na2CO3 + 2HCl -> 2NaCl + CO2 + H2O Find moles HCl by---Molarity = moles of solute/Liters of solution (18.1 ml = 0.0181 L) 0.23 M HCl = moles HCl/0.0181 liters = 0.004163 moles HCl Drive back against sodium carbonate stoichometrically 0.004163 moles HCl (1 mole Na2CO3/2 mole HCl)(105.99 grams/1 mole Na2CO3) = 0.22 grams Na2CO3 needed --------------------------------------------
How many grams of HCl are needed to obtain 1.0 liter of a 0.22 M HCl solution?
First.Molarity = moles of solute/Liters of solution0.22 M HCl = X moles/1.0 L= 0.22 moles HCl--------------------------Second.0.22 moles HCl (36.458 grams/1 mole HCl)= 8.0 grams hydrochloric acid needed===========================
