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0.1868 moles
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How many moles of kbr are present in 25ml of a 1.5 M solution?
Molarity = moles of solute/Liters of solution ( 25 ml = 0.025 Liters ) 1.5 M KBr = moles KBr/0.025 Liters = 0.038 moles potassium bromide ------------------
How many moles of KBr will be produced from 7 moles of BaBr2?
None, unless there is metallic potassium in the reaction mixture. Assuming excess potassium metal is present then 14 moles of KBr can be produced. 7BaBr2 + excess potassium -----> 14KBr + 7 Ba
How many moles of KBr will be produced from 4.79 moles of BaBr2?
14.17 mol BaBr2 has 2*14.17 mol Br in it, so 28.34 mol KBr can be produced (also 28.34 mol K is needed)
How many moles of KBr are present in 110mL of a 0.290M solution?
0.29M = 0.29 moles in 1000 ml so 0.29 x 110/1000 = 0.0319 moles
How many grams are in 3 mole of KBr?
Easy...the periodic table gives the average mole weight of each element averaged out over all it's naturally occurring, if any, isotopes, i.e., K is 39.09 Br is 79.9 Add them up and it's (to three significant figures): So KBr is 119 g/mole
How many moles are contained in 22.23 g KBr-?
0.1868 moles
How many moles are contained in 245g of potassium bromide?
Potassium bromide is KBr, the atomic mass of this compound is ca. 119.1. no.moles = mass/relitive molecular mass, so in this case that's 245/119.1 = 2.057 moles of KBr.
How many moles of kbr are present in 25ml of a 1.5 M solution?
Molarity = moles of solute/Liters of solution ( 25 ml = 0.025 Liters ) 1.5 M KBr = moles KBr/0.025 Liters = 0.038 moles potassium bromide ------------------
How many moles of potassium bromide can be produced from the reaction of 2.92 moles of potassium with 1.78 moles of bromine gas?
First write a balanced chemical equation: 2K + Br2 ---> 2KBR Find the limiting reactant by using the moles of each element and determining which one gives you the smallest number of moles of potassium bromide. 2.92 mol K (2 mol KBr/2 mol K)= 2.92 mol KBr 1.78 mol Br2 (2 mol KBR/1 mol Br2)=3.56 mol KBr potassium is your limiting reactant so the max. number of moles of KBr that can be produced is 2.92 mol of KBr
How many moles of KBr are present in 190mL of a 0.265M solution?
The answer is 0,0509 mole.
How many moles of KBr will be produced from 7 moles of BaBr2?
None, unless there is metallic potassium in the reaction mixture. Assuming excess potassium metal is present then 14 moles of KBr can be produced. 7BaBr2 + excess potassium -----> 14KBr + 7 Ba
How many moles of KBr will be produced from 14.17 moles of BaBr2?
14.17 mol BaBr2 has 2*14.17 mol Br in it, so 28.34 mol KBr can be produced (also 28.34 mol K is needed)
How many moles of KBr will be produced from 4.79 moles of BaBr2?
14.17 mol BaBr2 has 2*14.17 mol Br in it, so 28.34 mol KBr can be produced (also 28.34 mol K is needed)
How many moles of k are needed to form 3.3 moles of KBr?
357
How many moles of KBr are present in 110mL of a 0.290M solution?
0.29M = 0.29 moles in 1000 ml so 0.29 x 110/1000 = 0.0319 moles
How many moles of KBR are there in 100 mL if a 0.75 M Solution?
There would be 0.75 moles in 1 liter of solution. You have 100 mL which is in fact 0.1 liters. so you would have 0.1 of 0.75 moles. 0.1 x 0.75 = 0.075 moles.
How many grams are in 3 mole of KBr?
Easy...the periodic table gives the average mole weight of each element averaged out over all it's naturally occurring, if any, isotopes, i.e., K is 39.09 Br is 79.9 Add them up and it's (to three significant figures): So KBr is 119 g/mole
