Easy...the Periodic Table gives the average mole weight of each element averaged out over all it's naturally occurring, if any, isotopes, i.e.,
K is 39.09
Br is 79.9
Add them up and it's (to three significant figures):
So KBr is 119 g/mole
The molar mass of an element corresponds to the atomic mass of the element (found on the periodic table). The atomic mass of Sodium-Na is 22.990 g, which is also the molar mass of Na. So for 1 mole of Na, there are 22.990 grams of Na. If we had 3 moles of Na, then we would simply multiply the molar mass by 3.
The molar mass of sulfur is approximately 32 grams per mole. Therefore, 100 grams of sulfur would contain approximately 3 moles of sulfur atoms (100 grams / 32 grams/mole). To find the number of atoms, you would then multiply the number of moles by Avogadro's number (6.022 x 10^23 atoms/mole) to get the total number of sulfur atoms in 100 grams.
You can have any weight of sodium you want down to 0.00000000000000000000003847 grams, the approximate weight of one sodium atom
To determine the grams of V2O3 needed, we first find the number of moles of oxygen atoms in 7.56e11 atoms. Then, using the molar ratio in V2O3 (2 moles of oxygen for every mole of V2O3), we find the moles of V2O3. Finally, we convert moles to grams using the molar mass of V2O3.
Yes.Explanationary:27 g Al = 1.0 mole Al24 g = 1.5 mole O2 so this ratio (in mole) is 1:1.52Al + 3O2 --> Al2O3 so the balanced mole ratio is 2:3 or 1:1.5
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3 moles of ammonia is 51grams. One mole is 17 grams.
60 g
90.19 grams/mole
The molar mass of an element corresponds to the atomic mass of the element (found on the periodic table). The atomic mass of Sodium-Na is 22.990 g, which is also the molar mass of Na. So for 1 mole of Na, there are 22.990 grams of Na. If we had 3 moles of Na, then we would simply multiply the molar mass by 3.
For this you need the atomic (molecular) mass of Fe2(SO4)3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. Fe2(SO4)3=400.1 grams768 grams Fe2(SO4)3 / (400.1 grams) = 1.92 moles Fe2(SO4)3
Quite a few! 698 grams Al(NO3)3 (1 mole Al(NO3)3/213.01 grams)(9 moles O/1 mole Al(NO3)3)(6.022 X 1023/1 mole O) = 1.78 X 1025 atoms of oxygen ======================
Let's see. 3 moles gold (197.0 grams/1 mole Au) = 591 grams of gold ----------------------------- 10 mole iron (55.85 grams/1 mole Fe) = 558.5 grams of iron ----------------------------- So, 3 moles of gold has more mass that 10 moles of iron. (heavier)
The molar mass of sulfur is approximately 32 grams per mole. Therefore, 100 grams of sulfur would contain approximately 3 moles of sulfur atoms (100 grams / 32 grams/mole). To find the number of atoms, you would then multiply the number of moles by Avogadro's number (6.022 x 10^23 atoms/mole) to get the total number of sulfur atoms in 100 grams.
Balanced equation first. 3Mg + N2 -> Mg3N2 55.3 grams Mg (1 mole Mg/24.31 grams)(1 mole Mg3N2/3 mole Mg)(100.95 grams/1 mole Mg3N2) = 76.5 grams Mg3N2 made ===================
86.13 grams/mole