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7.56 X 1011 atoms of oxygen (1 mole O/6.022 X 1023)(1 mole V2O3/3 mole O)(149.88 grams/1 mole V2O3)

= 6.27 X 10 -11 grams vanadium oxide

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Q: How many grams of v203 would you need to have 7.56e11 atoms of oxygen?
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