Wiki User
∙ 11y ago7.56 X 1011 atoms of oxygen (1 mole O/6.022 X 1023)(1 mole V2O3/3 mole O)(149.88 grams/1 mole V2O3)
= 6.27 X 10 -11 grams vanadium oxide
===========================
Wiki User
∙ 11y agoTo determine the grams of V2O3 needed, we first find the number of moles of oxygen atoms in 7.56e11 atoms. Then, using the molar ratio in V2O3 (2 moles of oxygen for every mole of V2O3), we find the moles of V2O3. Finally, we convert moles to grams using the molar mass of V2O3.
Just about 16 grams as what you have written in you question is Avogadro's number, which is a mole of anything. Oxygen is 16 grams per mole.
There are 6 moles of oxygen atoms in 2 moles of potassium dichromate (K2Cr2O7). Each mole of K2Cr2O7 contains 7 oxygen atoms, so 2 moles would contain 14 oxygen atoms. The molar mass of oxygen is 16 g/mol, so there would be 224 grams of oxygen in 2 moles of K2Cr2O7.
In potassium dichromate (K2Cr2O7), there are 7 oxygen atoms per molecule. Therefore, two moles of K2Cr2O7 would contain 14 moles of oxygen atoms. Each mole of oxygen atoms has a molar mass of approximately 16 grams, so there would be 224 grams of oxygen in two moles of potassium dichromate.
To find the weight of 4.2x10^24 atoms of oxygen, you need to know the atomic mass of oxygen. The molar mass of oxygen is about 16 grams per mole. So, you can calculate the weight by dividing the number of atoms by Avogadro's number to get the number of moles, and then multiply by the molar mass. In this case, it would be: (4.2x10^24 atoms) / (6.022x10^23 atoms/mol) * 16 grams/mol = approximately 112 grams.
The molar mass of oxygen is approximately 16 grams per mole. This means that one mole of oxygen molecules (O2) would have a mass of 32 grams, since each molecule of O2 consists of 2 oxygen atoms.
Just about 16 grams as what you have written in you question is Avogadro's number, which is a mole of anything. Oxygen is 16 grams per mole.
To convert grams of oxygen to atoms of oxygen, you would multiply by Avogadro's number, which is approximately 6.022 x 10^23 atoms/mol. This conversion allows you to move from the unit of mass (grams) to the unit of atoms.
The mass of 2.000 mol of oxygen atoms is 32.00 grams.
There are 6 moles of oxygen atoms in 2 moles of potassium dichromate (K2Cr2O7). Each mole of K2Cr2O7 contains 7 oxygen atoms, so 2 moles would contain 14 oxygen atoms. The molar mass of oxygen is 16 g/mol, so there would be 224 grams of oxygen in 2 moles of K2Cr2O7.
In potassium dichromate (K2Cr2O7), there are 7 oxygen atoms per molecule. Therefore, two moles of K2Cr2O7 would contain 14 moles of oxygen atoms. Each mole of oxygen atoms has a molar mass of approximately 16 grams, so there would be 224 grams of oxygen in two moles of potassium dichromate.
16.01 grams in a mole of Oxygen. This can be found underneath the atomic symbol on a periodic table.
The molar mass of oxygen is approximately 16 g/mol. Therefore, the mass of 0.2 moles of oxygen atoms would be 0.2 moles x 16 g/mol = 3.2 grams.
To find the weight of 4.2x10^24 atoms of oxygen, you need to know the atomic mass of oxygen. The molar mass of oxygen is about 16 grams per mole. So, you can calculate the weight by dividing the number of atoms by Avogadro's number to get the number of moles, and then multiply by the molar mass. In this case, it would be: (4.2x10^24 atoms) / (6.022x10^23 atoms/mol) * 16 grams/mol = approximately 112 grams.
The molar mass of oxygen is approximately 16 grams per mole. This means that one mole of oxygen molecules (O2) would have a mass of 32 grams, since each molecule of O2 consists of 2 oxygen atoms.
To find the mass of 3 moles of oxygen atoms, you need to know the molar mass of oxygen. The molar mass of oxygen is approximately 16 grams per mole. So, for 3 moles of oxygen atoms, the mass would be 3 moles x 16 grams/mole = 48 grams.
In 2 moles of potassium dichromate, there are 16 moles of oxygen atoms (from the two oxygen atoms in each formula unit). The molar mass of oxygen is 16 g/mol, so in 2 moles of potassium dichromate, there are 32 grams of oxygen.
To determine the mass of oxygen in 147.2 grams of glucose (C6H12O6), we need to consider the molecular formula of glucose. For each mole of glucose, there are 6 moles of oxygen atoms. The molar mass of glucose is approximately 180.16 g/mol. Thus, the mass of oxygen in 147.2 grams of glucose would be (6/180.16) * 147.2 = approximately 4.88 grams.