2.000 moles of oxygen atoms weigh 32.00 g. 2.000 moles of oxygen molecules, on the other hand, weigh 64.00 g.
To calculate the number of oxygen atoms in 16.0 pounds of oxygen, first convert 16.0 pounds to grams (1 pound ≈ 453.592 grams). Then, calculate the number of moles of oxygen using the molar mass of oxygen (16.00 g/mol). Finally, use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of oxygen atoms.
At STP (Standard Temperature and Pressure), 1 mole of any ideal gas occupies 22.4 liters. Since 11.2 liters represent half the volume of a mole, we have 0.5 moles of O2 gas. Using the molar mass of oxygen (O2), which is around 32 g/mol, we find that 0.5 moles of O2 gas would be equivalent to approximately 16 grams.
15 moles of 02 equal 480 g.
There is no such thing as 02 gas. Perhaps you meant O2 gas, which is oxygen gas, consisting of molecules made of two oxygen atoms bonded together. O2 is essential for respiration in living organisms and combustion in fires.
The answer is 1,72 moles.
it is a molecule with two oxygen atoms..
Well, honey, if you're talking about 5.2g of O2, then we need to remember that oxygen comes in pairs in O2 molecules. So, one mole of O2 weighs 32g and contains 6.022 x 10^23 molecules, which means 5.2g of O2 would contain about 1 x 10^23 oxygen atoms. Hope that clears the air for you!
To calculate the number of oxygen atoms in 16.0 pounds of oxygen, first convert 16.0 pounds to grams (1 pound ≈ 453.592 grams). Then, calculate the number of moles of oxygen using the molar mass of oxygen (16.00 g/mol). Finally, use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of oxygen atoms.
Oxygen's chemical formula is 02 (2 oxygen atoms) and Ozone is O3 (three oxygen atoms), thus they are both forms of Oxygen
1 mole of 02 gas has 12,044 281 714.1023 atoms.
The balanced chemical equation for the reaction between oxygen and hydrogen is2H2 + 02 -> 2H2OThus 2.2 moles of oxygen reacts with 4.4 moles of hydrogen to form 4.4 moles of steam (water in gaseous state).The mass of H2O obtained is thus 4.4 x 18.0 = 79.2g.
See the Related Question linked the the left of this answer: = How do you solve an Ideal Gas Law problem? = Note that STP is standard temperature and pressure. Standard pressure is 1 atm, and standard temperature is 0 °C, which is 273.15 Kelvin.
At STP (Standard Temperature and Pressure), 1 mole of any ideal gas occupies 22.4 liters. Since 11.2 liters represent half the volume of a mole, we have 0.5 moles of O2 gas. Using the molar mass of oxygen (O2), which is around 32 g/mol, we find that 0.5 moles of O2 gas would be equivalent to approximately 16 grams.
The element O2 (oxygen gas) is made up of two oxygen atoms bonded together.
Oxygen can be found as an isolated atom, so one atom of oxygen is in one atom of oxygen. Oxygen can also bond with itself. 02, the oxygen you inhale and is used in combustion reactions, has 2 atoms. 03 is ozone, which is found in the ozone layer, and has 3 atoms.
15 moles of 02 equal 480 g.
Since there are two oxygen molecules, the molar mass would be twice the atomic weight given in the periodic table of elements. O = 16 g/mole O2 = 32 g/mole