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What is the mass in grams of 1mole of oxygen?
The mass of 2.000 mol of oxygen atoms is 32.00 grams.
How many grams of oxygen are contained in 18g of water?
The molar mass of water(H2O)=18((1*2)+16)The no. of moles(n) of water in 18 g of water=mass/molar mass=18 g/ 18 g mol-1 =1 molThe no. of molecules of water in 18 of water=n*Avogadro no. =1 mol*6.022*1023 mol-1 =6.022*1023The no. of atoms of oxygen in one mole of water=1 molThe no. of atoms of oxygen in 6.022*1023mol of water= 6.022*1023
How many oxygen atoms are present in 40.0 grams of oxygen gas?
Ar of O = 16g/mol Mr of O2 = 2(16) = 32g/mol Using the formula : Number of moles = mass / Mr Number of moles = 40g / 32g/mol = 1.25mols One mole of substance contains the same number of particles as the Avogadro constant, which is 6.02 x 10^23 Number of Oxygen molecules = 1.25 x 6.02 x 10^23 = 7.525 x 10^23 Each Oxygen molecules contain two Oxygen atoms Number of Oxygen atoms = 7.525 x 10^23 = 1.505 x 10^24 atoms
When 46g of sodium were exposed to dry air 62g of sodium oxide formed how many grams of oxygen from the air were used?
To find the amount of oxygen used, we need to consider the difference in mass between sodium and sodium oxide. The mass increase is 16g (62g - 46g) which corresponds to the amount of oxygen used from the air. Therefore, 16g of oxygen from the air were used.
How many grams of iron must be added to 16 grams of oxygen to equal 44 grams of iron 3 oxide?
30.8g of iron (approximately) reacted with 13.2g of oxygen will yield 44g of iron(III) oxide (Fe2O3) with 2.8g of oxygen left unreacted. This assumes atomic mass numbers of 56 and 16 respectively for iron and oxygen. The actual mass number of iron is 55.847 and oxygen 15.9994 making the figures 30.775g of iron and 13.225g of oxygen with 2.775g of unreacted oxygen. Of course this is an exothermic reaction so will there be a tiny tiny loss of mass in the system as it is converted to heat energy, according to E=MC^2? I'll let you work that one out...
How many atoms are present in 16g og Oxygen?
One mole of oxygen has a mass of 16 grams and contains 6.022 x 10^23 oxygen atoms. Therefore, 16 grams of oxygen will also contain 6.022 x 10^23 oxygen atoms.
How many atoms are present in 16g of O?
The Avogadro number: 6,02214129(27)×1023.
How many atoms in 16g of O and 8g of S?
In 16g of O, there are approximately 3.02 x 10^23 atoms, as the atomic mass of oxygen is 16 g/mol. In 8g of S, there are approximately 6.02 x 10^23 atoms, as the atomic mass of sulfur is 32 g/mol.
If 16g of oxygen contains 1 mole of oxygen atoms calculate the mass of one atom of oxygen in grams?
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How many atoms are in 16 grams of oxygen?
1mol O = 16.0g (rounded to 1 decimal place) 1mol O atoms = 6.022 x 1023 atoms 16g O x 1mol/16g = 1mol O 1mol O x 6.022 x 1023atoms/mol = 6.022 x 1023 atoms O
How many atoms are in 16g O and 8g S?
To find the number of atoms in 16g of oxygen (O) and 8g of sulfur (S), we first calculate the number of moles for each element. Oxygen has a molar mass of about 16 g/mol, so 16g of O corresponds to 1 mole (6.02 x 10²³ atoms). Sulfur has a molar mass of about 32 g/mol, so 8g of S corresponds to 0.25 moles (1.51 x 10²³ atoms). Therefore, the total number of atoms is 1.76 x 10²³ (1 mole of O + 0.25 moles of S).
What is the mass in grams of 1mole of oxygen?
The mass of 2.000 mol of oxygen atoms is 32.00 grams.
How many grams of oxygen are contained in 18g of water?
The molar mass of water(H2O)=18((1*2)+16)The no. of moles(n) of water in 18 g of water=mass/molar mass=18 g/ 18 g mol-1 =1 molThe no. of molecules of water in 18 of water=n*Avogadro no. =1 mol*6.022*1023 mol-1 =6.022*1023The no. of atoms of oxygen in one mole of water=1 molThe no. of atoms of oxygen in 6.022*1023mol of water= 6.022*1023
How many atoms in 16g of O?
The Avogadro number: 6,02214129(27)×1023.
How many number of moles of carbon dioxide that are contain 16g of oxygen?
To calculate the moles of carbon dioxide, we first need to determine the number of moles of oxygen in 16g. Using oxygen's molar mass of 16 g/mol, we find that there is 1 mole of oxygen in 16g. Since one mole of oxygen reacts with one mole of carbon dioxide in the balanced equation, there will also be 1 mole of carbon dioxide formed.
How many atoms are present in 16g of O and 8g of S?
To calculate the number of atoms present in a given mass of a substance, we need to use the concept of molar mass and Avogadro's number. The molar mass of oxygen (O) is approximately 16 g/mol, and the molar mass of sulfur (S) is approximately 32 g/mol. For oxygen: 16g / 16 g/mol = 1 mol of O. 1 mol of O contains 6.022 x 10^23 atoms (Avogadro's number). Therefore, 16g of O contains 6.022 x 10^23 atoms. For sulfur: 8g / 32 g/mol = 0.25 mol of S. 0.25 mol of S contains 0.25 x 6.022 x 10^23 atoms = 1.5055 x 10^23 atoms. Therefore, there are approximately 6.022 x 10^23 atoms in 16g of oxygen and approximately 1.5055 x 10^23 atoms in 8g of sulfur.
How many moles of atoms are there in 3.968x1023 atoms Mg?
Divide that number by Avogadro's number: 3.968x10(23) / 6.02x10(23) = 0.659mol Mg, which would be about 16g.
