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The Avogadro number: 6,02214129(27)×1023.

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How many atoms are in 16 grams of oxygen?

1mol O = 16.0g (rounded to 1 decimal place) 1mol O atoms = 6.022 x 1023 atoms 16g O x 1mol/16g = 1mol O 1mol O x 6.022 x 1023atoms/mol = 6.022 x 1023 atoms O


How many atoms in 16g of O?

The Avogadro number: 6,02214129(27)×1023.


How many atoms in 16g of O and 8g of S?

In 16g of O, there are approximately 3.02 x 10^23 atoms, as the atomic mass of oxygen is 16 g/mol. In 8g of S, there are approximately 6.02 x 10^23 atoms, as the atomic mass of sulfur is 32 g/mol.


How many O atoms are present in sodium chlorate?

There are 3 oxygen atoms present in sodium chlorate (NaClO3).


How many O atoms are present in sodium chlorite?

There are 2 oxygen atoms in 1 formula unit of sodium chlorite (NaClO2)


How many atoms of O would be present in one mole of acetic acid?

2


How many atoms are present in 16g of O and 8g of S?

To calculate the number of atoms present in a given mass of a substance, we need to use the concept of molar mass and Avogadro's number. The molar mass of oxygen (O) is approximately 16 g/mol, and the molar mass of sulfur (S) is approximately 32 g/mol. For oxygen: 16g / 16 g/mol = 1 mol of O. 1 mol of O contains 6.022 x 10^23 atoms (Avogadro's number). Therefore, 16g of O contains 6.022 x 10^23 atoms. For sulfur: 8g / 32 g/mol = 0.25 mol of S. 0.25 mol of S contains 0.25 x 6.022 x 10^23 atoms = 1.5055 x 10^23 atoms. Therefore, there are approximately 6.022 x 10^23 atoms in 16g of oxygen and approximately 1.5055 x 10^23 atoms in 8g of sulfur.


How many atoms of s and o were present in the reaction 2so2 plus o2--2so3?

In the reaction 2SO2 + O2 → 2SO3, there are 4 atoms of sulfur (S) present on the left side and 4 atoms of sulfur on the right side. There are 6 atoms of oxygen (O) on the left side and 6 atoms of oxygen on the right side.


How many atoms are presented to NaOH?

There are 3 atoms present: 1 sodium (Na), 1 oxygen (O), and 1 hydrogen (H).


How many atoms are present in the compound CO2?

Three atoms are present, in one molecule of carbon dioxide. They are 1 x Carbon 2 x Oxygen They are bonded as in the following diagram 'O=C=O'. That is each oxygen doubly bonds to the one carbon. Hence the formula is 'CO2'.


How many atoms are present in the compound K2CO3?

K= 2 C= 1 O=3 K2CO3= 6 atoms


How many types of atoms are present in Na2SO4?

Na2SO4Three different types of atoms.2 atoms of sodium.1 atom of sulfur.4 atoms of oxygen.This compound is called,sodium sulfate.