0
What else can I help you with?
How many atoms in 16g of O and 8g of S?
In 16g of O, there are approximately 3.02 x 10^23 atoms, as the atomic mass of oxygen is 16 g/mol. In 8g of S, there are approximately 6.02 x 10^23 atoms, as the atomic mass of sulfur is 32 g/mol.
How many atoms are presented to NaOH?
There are 3 atoms present: 1 sodium (Na), 1 oxygen (O), and 1 hydrogen (H).
How many atoms of element O are represented in the formula?
To determine the number of oxygen (O) atoms in a formula, you need to specify the compound or molecule in question. Once you provide the formula, I can help you calculate the number of oxygen atoms present.
How many moles of atoms are in 4.1 x 10-12g O?
To find the number of moles of atoms in 4.1 x 10^(-12) g of oxygen, you first convert the mass to moles by dividing by the molar mass of oxygen (16 g/mol). 4.1 x 10^(-12) g / 16 g/mol = 2.56 x 10^(-13) moles of oxygen atoms.
How many atoms are in urea?
The number of atoms in urea will depend on the number of urea molecules present. In one MOLECULE of urea there are 8 atoms. There are 2 N atoms, 4 H atoms, 1 C atom and 1 O atom. The structural formula of urea is H2NC(O)NH2
How many atoms are in 16 grams of oxygen?
1mol O = 16.0g (rounded to 1 decimal place) 1mol O atoms = 6.022 x 1023 atoms 16g O x 1mol/16g = 1mol O 1mol O x 6.022 x 1023atoms/mol = 6.022 x 1023 atoms O
How many atoms in 16g of O?
The Avogadro number: 6,02214129(27)×1023.
How many atoms in 16g of O and 8g of S?
In 16g of O, there are approximately 3.02 x 10^23 atoms, as the atomic mass of oxygen is 16 g/mol. In 8g of S, there are approximately 6.02 x 10^23 atoms, as the atomic mass of sulfur is 32 g/mol.
How many O atoms are present in sodium chlorate?
There are 3 oxygen atoms present in sodium chlorate (NaClO3).
How many O atoms are present in sodium chlorite?
There are 2 oxygen atoms in 1 formula unit of sodium chlorite (NaClO2)
How many atoms of O would be present in one mole of acetic acid?
2
How many atoms are present in 16g of O and 8g of S?
To calculate the number of atoms present in a given mass of a substance, we need to use the concept of molar mass and Avogadro's number. The molar mass of oxygen (O) is approximately 16 g/mol, and the molar mass of sulfur (S) is approximately 32 g/mol. For oxygen: 16g / 16 g/mol = 1 mol of O. 1 mol of O contains 6.022 x 10^23 atoms (Avogadro's number). Therefore, 16g of O contains 6.022 x 10^23 atoms. For sulfur: 8g / 32 g/mol = 0.25 mol of S. 0.25 mol of S contains 0.25 x 6.022 x 10^23 atoms = 1.5055 x 10^23 atoms. Therefore, there are approximately 6.022 x 10^23 atoms in 16g of oxygen and approximately 1.5055 x 10^23 atoms in 8g of sulfur.
How many atoms of s and o were present in the reaction 2so2 plus o2--2so3?
In the reaction 2SO2 + O2 → 2SO3, there are 4 atoms of sulfur (S) present on the left side and 4 atoms of sulfur on the right side. There are 6 atoms of oxygen (O) on the left side and 6 atoms of oxygen on the right side.
How many atoms are presented to NaOH?
There are 3 atoms present: 1 sodium (Na), 1 oxygen (O), and 1 hydrogen (H).
How many atoms are present in the compound CO2?
Three atoms are present, in one molecule of carbon dioxide. They are 1 x Carbon 2 x Oxygen They are bonded as in the following diagram 'O=C=O'. That is each oxygen doubly bonds to the one carbon. Hence the formula is 'CO2'.
How many atoms are present in the compound K2CO3?
K= 2 C= 1 O=3 K2CO3= 6 atoms
How many types of atoms are present in Na2SO4?
Na2SO4Three different types of atoms.2 atoms of sodium.1 atom of sulfur.4 atoms of oxygen.This compound is called,sodium sulfate.
