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The Avogadro number: 6,02214129(27)×1023.

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How many atoms in 16g of O and 8g of S?

In 16g of O, there are approximately 3.02 x 10^23 atoms, as the atomic mass of oxygen is 16 g/mol. In 8g of S, there are approximately 6.02 x 10^23 atoms, as the atomic mass of sulfur is 32 g/mol.


How many atoms are in 16g O and 8g S?

To find the number of atoms in 16g of oxygen (O) and 8g of sulfur (S), we first calculate the number of moles for each element. Oxygen has a molar mass of about 16 g/mol, so 16g of O corresponds to 1 mole (6.02 x 10²³ atoms). Sulfur has a molar mass of about 32 g/mol, so 8g of S corresponds to 0.25 moles (1.51 x 10²³ atoms). Therefore, the total number of atoms is 1.76 x 10²³ (1 mole of O + 0.25 moles of S).


How many atoms are present in 16g of o and 8g pf sulphur?

To find the number of atoms in 16 g of oxygen (O), we first determine the number of moles: 16 g of O divided by its molar mass (approximately 16 g/mol) gives 1 mole of O, which contains about 6.022 x 10²³ atoms. For 8 g of sulfur (S), the molar mass is approximately 32 g/mol, so 8 g corresponds to 0.25 moles, equating to about 1.505 x 10²³ atoms of S. In total, there are approximately 7.527 x 10²³ atoms from both elements combined.


How many atoms are presented to NaOH?

There are 3 atoms present: 1 sodium (Na), 1 oxygen (O), and 1 hydrogen (H).


How many atoms of element O are represented in the formula?

To determine the number of oxygen (O) atoms in a formula, you need to specify the compound or molecule in question. Once you provide the formula, I can help you calculate the number of oxygen atoms present.

Related Questions

How many atoms are in 16 grams of oxygen?

1mol O = 16.0g (rounded to 1 decimal place) 1mol O atoms = 6.022 x 1023 atoms 16g O x 1mol/16g = 1mol O 1mol O x 6.022 x 1023atoms/mol = 6.022 x 1023 atoms O


How many atoms in 16g of O?

The Avogadro number: 6,02214129(27)×1023.


How many atoms in 16g of O and 8g of S?

In 16g of O, there are approximately 3.02 x 10^23 atoms, as the atomic mass of oxygen is 16 g/mol. In 8g of S, there are approximately 6.02 x 10^23 atoms, as the atomic mass of sulfur is 32 g/mol.


How many atoms are in 16g O and 8g S?

To find the number of atoms in 16g of oxygen (O) and 8g of sulfur (S), we first calculate the number of moles for each element. Oxygen has a molar mass of about 16 g/mol, so 16g of O corresponds to 1 mole (6.02 x 10²³ atoms). Sulfur has a molar mass of about 32 g/mol, so 8g of S corresponds to 0.25 moles (1.51 x 10²³ atoms). Therefore, the total number of atoms is 1.76 x 10²³ (1 mole of O + 0.25 moles of S).


How many O atoms are present in sodium chlorate?

There are 3 oxygen atoms present in sodium chlorate (NaClO3).


How many O atoms are present in sodium chlorite?

There are 2 oxygen atoms in 1 formula unit of sodium chlorite (NaClO2)


How many atoms of O would be present in one mole of acetic acid?

2


How many atoms are present in 16g of o and 8g pf sulphur?

To find the number of atoms in 16 g of oxygen (O), we first determine the number of moles: 16 g of O divided by its molar mass (approximately 16 g/mol) gives 1 mole of O, which contains about 6.022 x 10²³ atoms. For 8 g of sulfur (S), the molar mass is approximately 32 g/mol, so 8 g corresponds to 0.25 moles, equating to about 1.505 x 10²³ atoms of S. In total, there are approximately 7.527 x 10²³ atoms from both elements combined.


How many atoms are present in 16g of O and 8g of S?

To calculate the number of atoms present in a given mass of a substance, we need to use the concept of molar mass and Avogadro's number. The molar mass of oxygen (O) is approximately 16 g/mol, and the molar mass of sulfur (S) is approximately 32 g/mol. For oxygen: 16g / 16 g/mol = 1 mol of O. 1 mol of O contains 6.022 x 10^23 atoms (Avogadro's number). Therefore, 16g of O contains 6.022 x 10^23 atoms. For sulfur: 8g / 32 g/mol = 0.25 mol of S. 0.25 mol of S contains 0.25 x 6.022 x 10^23 atoms = 1.5055 x 10^23 atoms. Therefore, there are approximately 6.022 x 10^23 atoms in 16g of oxygen and approximately 1.5055 x 10^23 atoms in 8g of sulfur.


How many atoms of s and o were present in the reaction 2so2 plus o2--2so3?

In the reaction 2SO2 + O2 → 2SO3, there are 4 atoms of sulfur (S) present on the left side and 4 atoms of sulfur on the right side. There are 6 atoms of oxygen (O) on the left side and 6 atoms of oxygen on the right side.


How many atoms are presented to NaOH?

There are 3 atoms present: 1 sodium (Na), 1 oxygen (O), and 1 hydrogen (H).


How many atoms are present in the compound CO2?

Three atoms are present, in one molecule of carbon dioxide. They are 1 x Carbon 2 x Oxygen They are bonded as in the following diagram 'O=C=O'. That is each oxygen doubly bonds to the one carbon. Hence the formula is 'CO2'.