The Avogadro number: 6,02214129(27)×1023.
In 16g of O, there are approximately 3.02 x 10^23 atoms, as the atomic mass of oxygen is 16 g/mol. In 8g of S, there are approximately 6.02 x 10^23 atoms, as the atomic mass of sulfur is 32 g/mol.
There are 3 atoms present: 1 sodium (Na), 1 oxygen (O), and 1 hydrogen (H).
To determine the number of oxygen (O) atoms in a formula, you need to specify the compound or molecule in question. Once you provide the formula, I can help you calculate the number of oxygen atoms present.
To find the number of moles of atoms in 4.1 x 10^(-12) g of oxygen, you first convert the mass to moles by dividing by the molar mass of oxygen (16 g/mol). 4.1 x 10^(-12) g / 16 g/mol = 2.56 x 10^(-13) moles of oxygen atoms.
The number of atoms in urea will depend on the number of urea molecules present. In one MOLECULE of urea there are 8 atoms. There are 2 N atoms, 4 H atoms, 1 C atom and 1 O atom. The structural formula of urea is H2NC(O)NH2
1mol O = 16.0g (rounded to 1 decimal place) 1mol O atoms = 6.022 x 1023 atoms 16g O x 1mol/16g = 1mol O 1mol O x 6.022 x 1023atoms/mol = 6.022 x 1023 atoms O
The Avogadro number: 6,02214129(27)×1023.
In 16g of O, there are approximately 3.02 x 10^23 atoms, as the atomic mass of oxygen is 16 g/mol. In 8g of S, there are approximately 6.02 x 10^23 atoms, as the atomic mass of sulfur is 32 g/mol.
There are 3 oxygen atoms present in sodium chlorate (NaClO3).
There are 2 oxygen atoms in 1 formula unit of sodium chlorite (NaClO2)
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To calculate the number of atoms present in a given mass of a substance, we need to use the concept of molar mass and Avogadro's number. The molar mass of oxygen (O) is approximately 16 g/mol, and the molar mass of sulfur (S) is approximately 32 g/mol. For oxygen: 16g / 16 g/mol = 1 mol of O. 1 mol of O contains 6.022 x 10^23 atoms (Avogadro's number). Therefore, 16g of O contains 6.022 x 10^23 atoms. For sulfur: 8g / 32 g/mol = 0.25 mol of S. 0.25 mol of S contains 0.25 x 6.022 x 10^23 atoms = 1.5055 x 10^23 atoms. Therefore, there are approximately 6.022 x 10^23 atoms in 16g of oxygen and approximately 1.5055 x 10^23 atoms in 8g of sulfur.
In the reaction 2SO2 + O2 → 2SO3, there are 4 atoms of sulfur (S) present on the left side and 4 atoms of sulfur on the right side. There are 6 atoms of oxygen (O) on the left side and 6 atoms of oxygen on the right side.
There are 3 atoms present: 1 sodium (Na), 1 oxygen (O), and 1 hydrogen (H).
Three atoms are present, in one molecule of carbon dioxide. They are 1 x Carbon 2 x Oxygen They are bonded as in the following diagram 'O=C=O'. That is each oxygen doubly bonds to the one carbon. Hence the formula is 'CO2'.
K= 2 C= 1 O=3 K2CO3= 6 atoms
Na2SO4Three different types of atoms.2 atoms of sodium.1 atom of sulfur.4 atoms of oxygen.This compound is called,sodium sulfate.