The mass of 2.000 mol of oxygen atoms is 32.00 grams.
The total mass of the products would be 10 grams, as mass is conserved in a chemical reaction. When water decomposes into its elements, hydrogen and oxygen, the total mass of the products will be the same as the mass of the reactant.
an equation showing conservation of mass of reactants and products:2H2O --> 2H2 & O2what is the mass of the oxygen gas produced, from 178.8 g H2O , (using molar masses:178.8 g H2O @ (1mol O2)(@ 32.00 g/mol) / (2molH2O)(18.02g/mol) =your answer (4 sigfigs): 158.8 g O2178.8 g H2O ---> 20.0 H2 & 158.8 O2
Given that approximately 16 grams of oxygen contains a mole of oxygen atoms, the weight of an oxygen atom in grams can be solved by dividing by Avogadro's number. 16/(6.02 x 10^23) is equal to approximately 2.66 x 10 ^ -23 g, which is the approximate weight of an oxygen atom in grams.
To calculate the mass of 1.5 moles of oxygen molecules (O2), you multiply the number of moles (1.5) by the molar mass of oxygen (O2). The molar mass of O2 is approximately 32 g/mol. So, the mass of 1.5 moles of oxygen molecules would be 1.5 moles * 32 g/mol = 48 grams.
For this you need the atomic mass of Ca. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.125 grams Ca / (40.1 grams) = 3.12 moles Ca
The molar mass of oxygen is approximately 16 grams/mol. Therefore, the mass of 0.8 grams of oxygen is equivalent to 0.8/16 = 0.05 moles.
The molar mass of oxygen is approximately 16 grams/mol. Therefore, the mass of 3 moles of oxygen would be 3 moles * 16 grams/mole = 48 grams.
The molar mass of oxygen is approximately 16.00 grams per mole. Therefore, the mass of 1.0 mole of oxygen is 16.00 grams.
16 grams or 32 grams, depending on what you're looking at.The mass of one mole of oxygen atoms is about 16 grams, but oxygen gas exists as a molecule (O2) so 1 mole of (O2) is 32 grams.
Just about 16 grams as what you have written in you question is Avogadro's number, which is a mole of anything. Oxygen is 16 grams per mole.
The percentage of oxygen is 54,84 %.
A mole of oxygen atoms has a mass of approximately 16 grams. A mole of O2 has a mass of approximately 32 grams. A mole is 6.02 x 1023 particles and as such a mole of oxygen atoms has only half the mass of a mole of oxygen molecules.
what is the mass in grams of oxygen, is needed to complete combustion of 6 L of methane?
To determine the mass of oxygen in 147.2 grams of glucose (C6H12O6), we need to consider the molecular formula of glucose. For each mole of glucose, there are 6 moles of oxygen atoms. The molar mass of glucose is approximately 180.16 g/mol. Thus, the mass of oxygen in 147.2 grams of glucose would be (6/180.16) * 147.2 = approximately 4.88 grams.
To find the mass of oxygen in 10.0 grams of water (H₂O), we first need to determine the molar mass of water, which is approximately 18.02 g/mol (16.00 g/mol for oxygen and 2.02 g/mol for hydrogen). The mass fraction of oxygen in water is about 16.00 g / 18.02 g, which is approximately 0.888. Therefore, in 10.0 grams of water, the mass of oxygen is roughly 10.0 g × 0.888 ≈ 8.88 grams.
Mass of Oxygen is approximately 16 grams. (15.9994 grams) per mole. Mass of Magnesium is approximately 24.305 grams per mole.
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