Given that approximately 16 grams of oxygen contains a mole of oxygen atoms, the weight of an oxygen atom in grams can be solved by dividing by Avogadro's number. 16/(6.02 x 10^23) is equal to approximately 2.66 x 10 ^ -23 g, which is the approximate weight of an oxygen atom in grams.
The ratio of mass of copper to oxygen in the sample is 4:1. This is determined by dividing the mass of copper (64 g) by the mass of oxygen (16 g).
To find the mass percent of oxygen in the compound, first calculate the total mass of the compound by adding the masses of carbon, hydrogen, and nitrogen. The total mass of the compound is 136.6 g (C) + 26.4 g (H) + 31.8 g (N) = 194.8 g. The mass of oxygen can be calculated by subtracting the total mass of the compound from the given mass of the sample: 230 g - 194.8 g = 35.2 g. Therefore, the mass percent of oxygen in the compound is (35.2 g / 230 g) x 100% ≈ 15.3%.
The molar mass of SO2 is 64.07 g/mol. Since oxygen has a molar mass of 16 g/mol and there are 2 oxygen atoms in SO2, the total mass of oxygen in SO2 is 32 g. Therefore, the mass percent of oxygen in SO2 is 32/64.07 * 100% = 50.05%.
The percent by mass of oxygen in N2O4 is 69,56 %.
The molar mass of SO3 is 80.06 g/mol, with oxygen contributing 48.00 g/mol, which is 60% of the total molar mass. Therefore, the approximate percent by mass of oxygen in SO3 is 60%.
To find the mass percent of oxygen in the compound, first calculate the total mass of the compound by adding the masses of magnesium and oxygen: 14.5 g + 3.5 g = 18.0 g. Then, use the formula for mass percent: (mass of oxygen / total mass) × 100%. Thus, the mass percent of oxygen is (3.5 g / 18.0 g) × 100% ≈ 19.44%.
The molar mass of SO2 is 64.07 g/mol. Oxygen has a molar mass of 16.00 g/mol. To calculate the mass percent of oxygen in SO2, we can divide the molar mass of oxygen (32.00 g) by the molar mass of SO2 (64.07 g) and multiply by 100 to get 50.05%.
The ratio of mass of copper to oxygen in the sample is 4:1. This is determined by dividing the mass of copper (64 g) by the mass of oxygen (16 g).
To find the mass percent of oxygen in the compound, first calculate the total mass of the compound by adding the masses of carbon, hydrogen, and nitrogen. The total mass of the compound is 136.6 g (C) + 26.4 g (H) + 31.8 g (N) = 194.8 g. The mass of oxygen can be calculated by subtracting the total mass of the compound from the given mass of the sample: 230 g - 194.8 g = 35.2 g. Therefore, the mass percent of oxygen in the compound is (35.2 g / 230 g) x 100% ≈ 15.3%.
To find the mass of oxygen in sulfuric acid (H2SO4), we first need to calculate the molar mass of the compound. The molar mass of H2SO4 is 98.08 g/mol. The molar mass of oxygen in H2SO4 is 4 * 16 = 64 g/mol. To find the mass of oxygen in 250 g of H2SO4, we can use the proportion: (64 g / 98.08 g) * 250 g = 161.3 g of oxygen.
The molar mass of MgO is 40.3 g/mol (24.3 g/mol for Mg and 16 g/mol for O). The mass of oxygen in MgO is 16 g, so the percent by mass of oxygen is (16 g / 40.3 g) x 100% ≈ 39.7%.
The answer is 2,871 g oxygen.
This mass is 2,469 g.
18 g or water will have 16 g of oxygen. So 9 g or water will have 8 g of oxygen.
The answer is 1,425 g oxygen.
The mass of 4.38 liters of oxygen is 6,259 g.
To find the percent mass of oxygen in xenon trioxide (XeO3), we first calculate the molar mass of XeO3. Xenon has a molar mass of 131.3 g/mol, and oxygen has a molar mass of 16.00 g/mol. So the molar mass of XeO3 is 131.3 + 3(16.00) = 179.3 g/mol. The mass of oxygen in XeO3 is 3(16.00) = 48.00 g. Therefore, the percent mass of oxygen in XeO3 is (48.00 g / 179.3 g) x 100% ≈ 26.73%.