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How many grams of potassium chloride are formed by the decomposition of excess potassium chlorate to yield 3.40 L of oxygen?
To determine the grams of potassium chloride formed, you first need to calculate the moles of oxygen produced by the decomposition of potassium chlorate. Then, use the stoichiometry of the balanced chemical equation to convert moles of oxygen to moles of potassium chloride. Finally, from the molar mass of potassium chloride, you can calculate the grams formed.
How many moles of potassium chloride are there in a 100.0g sample of potassium chloride?
To calculate the number of moles of potassium chloride in a 100.0g sample, you need to divide the mass of the sample by the molar mass of potassium chloride. The molar mass of potassium chloride is approximately 74.55 g/mol. Therefore, 100.0g ÷ 74.55 g/mol = approximately 1.34 moles of potassium chloride in the sample.
How many grams of potassium chloride are produced if 25 grams of potassium chlorate decompose into potassium chloride and oxygen?
Oh, dude, chemistry time! So, when 25 grams of potassium chlorate decompose, you get 74.55% potassium chloride and 25.45% oxygen. So, if you do the math, you'd get around 18.64 grams of potassium chloride. But hey, who's counting, right?
How many moles of potassium iodide are there in 50 grams?
For this you need the atomic (molecular) mass of KCl. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. KCl= 74.6 grams50.0 grams KCl / (74.6 grams) = .670 moles KCl
How many grams of potassium bromite (KBrO2) are there in 0.280 moles?
To calculate the grams of potassium bromite in 0.280 moles, you would multiply the number of moles by the molar mass of KBrO2, which is 119 g/mol. Therefore, 0.280 moles of KBrO2 would be 0.280 moles * 119 g/mol = 33.32 grams.
How many grams of potassium chloride are formed by the decomposition of excess potassium chlorate to yield 3.40 L of oxygen?
To determine the grams of potassium chloride formed, you first need to calculate the moles of oxygen produced by the decomposition of potassium chlorate. Then, use the stoichiometry of the balanced chemical equation to convert moles of oxygen to moles of potassium chloride. Finally, from the molar mass of potassium chloride, you can calculate the grams formed.
How many moles of potassium chloride are there in a 100.0g sample of potassium chloride?
To calculate the number of moles of potassium chloride in a 100.0g sample, you need to divide the mass of the sample by the molar mass of potassium chloride. The molar mass of potassium chloride is approximately 74.55 g/mol. Therefore, 100.0g ÷ 74.55 g/mol = approximately 1.34 moles of potassium chloride in the sample.
How many grams are in four tenths moles of sodium chloride?
23.3772 grams are there in four tenths moles of sodium chloride
How many grams are in 34.7 moles of potassium?
34,7 moles of potassium 1 356,7 g.
How many grams of potassium chloride are produced if 25 grams of potassium chlorate decompose into potassium chloride and oxygen?
Oh, dude, chemistry time! So, when 25 grams of potassium chlorate decompose, you get 74.55% potassium chloride and 25.45% oxygen. So, if you do the math, you'd get around 18.64 grams of potassium chloride. But hey, who's counting, right?
How many grams are in 0.40 moles of sodium chloride?
0,40 moles of sodium chloride contain 23,376 g.
How many moles are in 45 grams of potassium oxide?
45/94.2 is 0.4777 moles
How many grams of potassium sulfate are there in 25.3 moles?
25,3 moles of potassium sulfate hva a mass of 4,4409 kg.
How many moles are in 156 grams of potassium?
3.99 or 4
How many grams are in 2.2 moles of potassium sulfide?
242.594 g
How many milligrams of potassium are in a Klor-Con m20 tab?
Tablet Klor Con contains potassium chloride in it. 20 milliequivalent of potassium chloride equals to 1.5 grams of potassium chloride.
How many grams of potassium permanganate are in 2.20 moles?
To calculate the grams of potassium permanganate in 2.20 moles, you would need to know the molar mass of potassium permanganate. The molar mass of potassium permanganate (KMnO4) is about 158.034 g/mol. So, 2.20 moles of KMnO4 is equal to 2.20 moles x 158.034 g/mol = 347.67 grams of potassium permanganate.
