To find the number of moles in 12.0 g of calcium hydroxide, Ca(OH)₂, you first need to calculate its molar mass. The molar mass of Ca(OH)₂ is approximately 74.09 g/mol (calcium: 40.08 g/mol, oxygen: 16.00 g/mol, hydrogen: 1.01 g/mol). Using the formula ( \text{moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} ), you can calculate the moles: ( \frac{12.0 , \text{g}}{74.09 , \text{g/mol}} \approx 0.162 , \text{moles} ). Thus, there are approximately 0.162 moles of Ca(OH)₂ in 12.0 g.
The mass of 7,346 moles of Ca(OH)2 is 544,3 g.
120 g calcium is equal to 3 moles.
14,84 g magnesium are equivalent to 0,61 moles.
97,5 g of oxygen is equal to 5,416 moles.
978 g calcium contain 24,4 moles.
The mass of 7,346 moles of Ca(OH)2 is 544,3 g.
120 g calcium is equal to 3 moles.
n = 817 g x (1 mol / 120 g) = 6.81 mol
The mole of a metal, such as sodium, is generally assumed to consist of Avogadro's Number of single atoms. The gram atomic mass of sodium is 22.9898. The number of moles in 120 grams of Na is therefore 120/22.9898, or 5.22, rounded to the justified number of significant digits.
The formula is: number of moles = g Be/9,012.
14,84 g magnesium are equivalent to 0,61 moles.
97,5 g of oxygen is equal to 5,416 moles.
978 g calcium contain 24,4 moles.
67,4 g HCl is equivalent to 1,85 moles.
29,0 g of calcium is equal to 0,723 moles.
573,28 of g of AgCI is equivalent to 4 moles.
27.4 g H2O x 1 mole/18 g = 1.52 moles