n = 817 g x (1 mol / 120 g) = 6.81 mol
the formula does not show how many moles are in a compound, but it tells how many atoms of an element that are in the compound...
I assume double displacement reaction. Balanced equation. 3AgNO3 + Na3PO4 -> Ag3PO4 + 3NaNO3 2.00 moles sodium phosphate ( 3 moles AgNO3/1 mole Na3PO4) = 6.00 moles silver nitrate needed =========================
2,196.10-12 pmol of Na3PO4. (p is pico)
The formula mass of sodium triphosphate, Na3PO4 is 3(23.0)+31.0+4(16.0)=164.0 Amount of sodium triphosphate = 10/164.0 = 0.0610mol
The answer is 0,111 moles.
First, you have to know what kind of sodium phosphate! Is it NaH2PO4, Na2HPO4, or Na3PO4? In all three cases, the Na totally disassociates from rest of the molecule when you dissolve it in water. (And all are highly soluble in water.) Don't worry about the H atoms. They stay with the PO4. The solution's molarity is 2 molar. (Note that "molarity" is NOT a unit.) That means there are 2 moles of sodium phosphate per liter. 500 mL is half a liter, therefore the sample has half of 2 moles of sodium phosphate. So, 1 mole of sodium phosphate. Assuming you have NaH2PO4, then you have 1 mole of Na+ ions. For the other two chemicals, multiply by 2 or 3 as necessary. I'm not telling you how to convert moles to numbers. If you can't do that, you should flunk chemistry.
Every formula unit of sodium chloride has one sodium atom. Therefore, there are 4.0 moles of sodium ions in 4.0 moles of NaCl.
3.6
there are 4.5 moles
The answer is 1,668.10-4 moles.
How many formula units of sodium acetate are in 0.87 moles of sodium acetat
o.8 meq sodium