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How many grams of barium chloride are there in 286 moles?
To convert moles to grams, you need to use the molar mass of barium chloride, which is 208.23 g/mol. Multiply the number of moles (286 moles) by the molar mass to find the grams of barium chloride: 286 moles * 208.23 g/mol = 59,545.78 grams.
How many grams of CO2 will be produced by burning 34.3 gram of C3H8?
To calculate the amount of CO2 produced when burning 34.3 grams of C3H8 (propane), you need to balance the chemical equation for the combustion of C3H8. Since each mole of C3H8 produces 3 moles of CO2, you first convert 34.3 grams of C3H8 to moles, calculate the moles of CO2 produced, and then convert that to grams of CO2.
How many days does it take for 32 grams of palladium -103 to decay to 2.0 grams the half - life of palladium -103 is 17 days?
It would take 51 days for 32 grams of palladium-103 to decay to 2.0 grams. This calculation involves multiple half-lives, as every 17 days half of the remaining material decays. By dividing the initial mass by 2 repeatedly until you reach 2.0 grams, you find that it takes 3 half-lives for the decay to occur.
How many moles of nitrogen are in 650 moles of ammonium carbonate How many grams of this compound supply this much nitrogen?
The formula unit for the usual form of solid ammonium carbonate is (NH4)2CO3.H2O. This formula shows that each formula unit contains two atoms of nitrogen. Because nitrogen forms diatomic molecules at standard temperature and pressure, the number of moles of nitrogen is therefore the same as the number of formula units of ammonium carbonate, stated to be 650. The gram formula unit mass of this solid ammonium carbonate is 114.10. Therefore, 114.10(650) or 7.42 X 103 grams of the solid, to the justified number of significant digits, will be required.
How many atoms is in 2.3 moles of gallium?
How many atoms of gallium are in 2.85 x 103 g of gallium?
103 pounds equals how many grams?
103 pounds = about 46,700 grams.
How many pounds is 103 grams?
103 grams = 0.22707613 pounds103 grams = 0.23 pounds
How many grams of barium chloride are there in 286 moles?
To convert moles to grams, you need to use the molar mass of barium chloride, which is 208.23 g/mol. Multiply the number of moles (286 moles) by the molar mass to find the grams of barium chloride: 286 moles * 208.23 g/mol = 59,545.78 grams.
How many moles of Pb are equivalent to 9.51 times 103 g Pb?
To find the number of moles, you need to divide the given mass (9.51 x 10^3 g) by the molar mass of Pb. The molar mass of lead (Pb) is approximately 207.2 g/mol. So, 9.51 x 10^3 g Pb is equivalent to about 45.9 moles of Pb.
How many molecules of in 1.26 x 10 3 grams of c2h4?
The gram molecular mass of C2H4 is 28.05. Therefore, 1.26 X 103 grams constitutes (1.26/28.05) X 103 or about 44.9 moles. Each mole contains Avogadro's number of molecules; therefore, 1.26 X 103 grams contains 2.71 X 1025 molecules, to the justified number of significant digits.
How many molecules of ammonia are present in one milli mole of ammonia?
One mole=1000 Milli moles One mole=6.022 x 1023 molecules of the substance Therefore, one Milli mole of ammonia has 6.022 x 1023 /103 = 6.022 x 1020 molecules of ammonia.
How many grams of CO2 will be produced by burning 34.3 gram of C3H8?
To calculate the amount of CO2 produced when burning 34.3 grams of C3H8 (propane), you need to balance the chemical equation for the combustion of C3H8. Since each mole of C3H8 produces 3 moles of CO2, you first convert 34.3 grams of C3H8 to moles, calculate the moles of CO2 produced, and then convert that to grams of CO2.
What is the mass of a boron sample which contains 585 moles of b atoms?
Each mole of boron atoms has a mass of 10.811 grams, as indicated by the gram atomic mass or weight of boron. Therefore, 585 moles has a mass of about 6.32 X 103 grams, to the same number of significant digits as 585.
280 grams is equal to how many oz?
28 grams in an oz Source: Drug dealer
How many grams of C4H10O can be melted by 2.0 x 103 J?
20.4
How many grams of oxygen are required to burn 4.8 mol of butane?
The balanced equation for the reaction is 2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O. This shows that 13 moles of diatomic oxygen are required to burn 2 moles of butane. By proportionality, (4.8/2)13 or 31.2 moles of oxygen are required to burn 4.8 moles of butane. This corresponds to 31.2(32) or 1.0 X 103 grams of oxygen.
What is 6.8 kilogram in grams in scientific notation?
It is 6.8*103 grams.
