How many atoms of gallium are in 2.85 x 103 g of gallium?
To find the number of atoms in 0.35 moles of plutonium, you can use Avogadro's number, which is 6.022 x 10^23 atoms/mol. Multiply 0.35 moles by Avogadro's number to get the number of atoms. Therefore, 0.35 moles of plutonium contains approximately 2.1 x 10^23 atoms.
3,00 moles of Li have 18,066422571.10e23 atoms.
.385 moles of atoms are in 5.00 of 13c. 5/13 = 0.385 mol
5.66 x 10^23 atoms of xenon is equal to 0.094 moles.
There are (6.023 \times 10^{23}) atoms in 1 mole of any substance (Avogadro's number). Therefore, there are (1.004 \times 6.023 \times 10^{23} \approx 6.05 \times 10^{23}) atoms in 1.004 moles of bismuth.
To find the number of atoms in 0.39 moles of Ga (gallium), you first need to calculate the number of moles in 0.39 moles of Ga. Then, you can use Avogadro's number (6.022 x 10^23) to convert moles to atoms. So, for Ga, there would be approximately 2.35 x 10^23 atoms in 0.39 moles of Ga.
1.50 x 10 to the 23 atoms of fluorine is equal to 0,249 moles.
To find the number of atoms in 0.35 moles of plutonium, you can use Avogadro's number, which is 6.022 x 10^23 atoms/mol. Multiply 0.35 moles by Avogadro's number to get the number of atoms. Therefore, 0.35 moles of plutonium contains approximately 2.1 x 10^23 atoms.
Approx 7.925*10^23 atoms.
The answer is 7,829.10 ex.23 atoms.
0.125 moles x 6.02x10^23 atoms/mole = 7.53x10^22 atoms
There are 9.33 moles of carbon in 5.62 atoms of carbon.
Divide that number of atoms by 6.02x10^23 atoms/mole
3,00 moles of Li have 18,066422571.10e23 atoms.
2.01x10^22 atoms x 1 mole/6.02x10^23 atoms = 0.0334 moles
85 moles Li x 6.02x10^23 atoms/mole Li = 5.17x10^25 atoms of Li
0.3 moles K (6.022 X 10^23/1mol K) = 1.8 X 10^23 atoms of K