mol = mass/Mr mol = 737/ 58.44 moles of NaCl = 12.61
HClO3 molecular weight is 84.46g/mol. moles is mass/molecular weight. 1.25/84.46 is 0.0179999 moles
The answer is 0,0625 mol.
14.17 mol BaBr2 has 2*14.17 mol Br in it, so 28.34 mol KBr can be produced (also 28.34 mol K is needed)
Given the balanced equation Kr + 3F2 --> KrF6 In order to find how many moles of F2 are needed to produce 3.0 moles of KrF6, we must convert from moles to moles (mol --> mol conversion). 3.0 mol KrF6 * 3 molecules F2 = 9.0 mol F2 --------- 1 molecule F2
The molecular mass of iron III nitrate is 241.86g/mol. Mass divided by molecular weight gives moles, which is 0.02481 moles (6/241.86)
How many moles of CO2 are produced when 2.1 mol of C2H2 react?
4,51 moles hydrogen exist.
mol = mass/Mr mol = 737/ 58.44 moles of NaCl = 12.61
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
HClO3 molecular weight is 84.46g/mol. moles is mass/molecular weight. 1.25/84.46 is 0.0179999 moles
First write a balanced chemical equation: 2K + Br2 ---> 2KBR Find the limiting reactant by using the moles of each element and determining which one gives you the smallest number of moles of potassium bromide. 2.92 mol K (2 mol KBr/2 mol K)= 2.92 mol KBr 1.78 mol Br2 (2 mol KBR/1 mol Br2)=3.56 mol KBr potassium is your limiting reactant so the max. number of moles of KBr that can be produced is 2.92 mol of KBr
4.9 mol
1.5 moles
7 mol
The answer is 0,0625 mol.
14.17 mol BaBr2 has 2*14.17 mol Br in it, so 28.34 mol KBr can be produced (also 28.34 mol K is needed)