The answer is 0,0625 mol.
14.17 mol BaBr2 has 2*14.17 mol Br in it, so 28.34 mol KBr can be produced (also 28.34 mol K is needed)
Given the balanced equation Kr + 3F2 --> KrF6 In order to find how many moles of F2 are needed to produce 3.0 moles of KrF6, we must convert from moles to moles (mol --> mol conversion). 3.0 mol KrF6 * 3 molecules F2 = 9.0 mol F2 --------- 1 molecule F2
To determine if there are 143 g/mol in 6.80 g of Al₂O₃, we first need to calculate the molar mass of Al₂O₃. The molar mass of Al₂O₃ is approximately 102 g/mol (with aluminum at about 27 g/mol and oxygen at about 16 g/mol). To find the number of moles in 6.80 g of Al₂O₃, we divide the mass by the molar mass: 6.80 g ÷ 102 g/mol ≈ 0.067 moles. Thus, there are no 143 g/mol in 6.80 g of Al₂O₃; the molar mass is actually around 102 g/mol.
To find the number of moles in 737g of NaCl, first calculate the molar mass of NaCl, which is 58.44 g/mol. Then divide the given mass (737g) by the molar mass to get the number of moles. Number of moles = 737g / 58.44 g/mol ≈ 12.61 moles of NaCl.
How many moles of CO2 are produced when 2.1 mol of C2H2 react?
The balanced chemical equation for the reaction between H2 and NH3 is: 3H2 + N2 → 2NH3 From the equation, we can see that 3 moles of H2 produce 2 moles of NH3. Therefore, when 1.2 moles of H2 react, we can calculate the moles of NH3 produced as: 1.2 mol H2 * (2 mol NH3 / 3 mol H2) = 0.8 mol NH3.
4.9 mol
To determine the mass of iron(II) nitrate needed for 6.00 moles of Fe(NO3)2, you first need to calculate the molar mass of Fe(NO3)2. Fe(NO3)2 has a molar mass of approximately 179.86 g/mol. Therefore, the mass needed would be 6.00 moles * 179.86 g/mol ≈ 1079.16 grams of Fe(NO3)2.
The answer is 0,0625 mol.
14.17 mol BaBr2 has 2*14.17 mol Br in it, so 28.34 mol KBr can be produced (also 28.34 mol K is needed)
Given the balanced equation Kr + 3F2 --> KrF6 In order to find how many moles of F2 are needed to produce 3.0 moles of KrF6, we must convert from moles to moles (mol --> mol conversion). 3.0 mol KrF6 * 3 molecules F2 = 9.0 mol F2 --------- 1 molecule F2
To find the number of moles in 0.525g of AgCl, you need to divide the mass by the molar mass of AgCl. The molar mass of AgCl is 143.32 g/mol. moles = mass / molar mass moles = 0.525g / 143.32 g/mol moles ≈ 0.0037 mol
Since the ratio of moles of Al to moles of Al2O3 is 4:2, if 5.23 mol Al completely reacts, 2.615 mol Al2O3 can be made.
To find the number of moles in 737g of NaCl, first calculate the molar mass of NaCl, which is 58.44 g/mol. Then divide the given mass (737g) by the molar mass to get the number of moles. Number of moles = 737g / 58.44 g/mol ≈ 12.61 moles of NaCl.
The answer is 3,375 moles oxygen.
To find the number of moles, divide the given mass of argon by its molar mass. The molar mass of argon is approximately 39.95 g/mol. Number of moles of argon = 14.5 g / 39.95 g/mol Number of moles of argon = 0.362 moles