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How many moles of Mg3PO42 will contain 0.25 moles of oxygen atoms?
The answer is 0,0625 mol.
How many moles F2 are required to produce 3.0 moles KrF6 in the equation Kr plus 3F2 producing KrF6?
Given the balanced equation Kr + 3F2 --> KrF6 In order to find how many moles of F2 are needed to produce 3.0 moles of KrF6, we must convert from moles to moles (mol --> mol conversion). 3.0 mol KrF6 * 3 molecules F2 = 9.0 mol F2 --------- 1 molecule F2
How many moles of KBr will be produced from 14.17 moles of BaBr2?
14.17 mol BaBr2 has 2*14.17 mol Br in it, so 28.34 mol KBr can be produced (also 28.34 mol K is needed)
Is there 143g mol in 6.80g of al2o3?
To determine if there are 143 g/mol in 6.80 g of Al₂O₃, we first need to calculate the molar mass of Al₂O₃. The molar mass of Al₂O₃ is approximately 102 g/mol (with aluminum at about 27 g/mol and oxygen at about 16 g/mol). To find the number of moles in 6.80 g of Al₂O₃, we divide the mass by the molar mass: 6.80 g ÷ 102 g/mol ≈ 0.067 moles. Thus, there are no 143 g/mol in 6.80 g of Al₂O₃; the molar mass is actually around 102 g/mol.
How many moles of NaCl are in 737 g of NaCl?
To find the number of moles in 737g of NaCl, first calculate the molar mass of NaCl, which is 58.44 g/mol. Then divide the given mass (737g) by the molar mass to get the number of moles. Number of moles = 737g / 58.44 g/mol ≈ 12.61 moles of NaCl.
How many moles of CO2 are produced when 2.1 mol of C2H2 react?
How many moles of CO2 are produced when 2.1 mol of C2H2 react?
What mass of ironIIInitrate is needed for a chemical reaction that requires 6.00 moles of FeNO33?
To determine the mass of iron(II) nitrate needed for 6.00 moles of Fe(NO3)2, you first need to calculate the molar mass of Fe(NO3)2. Fe(NO3)2 has a molar mass of approximately 179.86 g/mol. Therefore, the mass needed would be 6.00 moles * 179.86 g/mol ≈ 1079.16 grams of Fe(NO3)2.
How many moles of NH3 are produced when 1.2 mol of H2 reacts?
The balanced chemical equation for the reaction between H2 and NH3 is: 3H2 + N2 → 2NH3 From the equation, we can see that 3 moles of H2 produce 2 moles of NH3. Therefore, when 1.2 moles of H2 react, we can calculate the moles of NH3 produced as: 1.2 mol H2 * (2 mol NH3 / 3 mol H2) = 0.8 mol NH3.
How many moles of Mg3PO42 will contain 0.25 moles of oxygen atoms?
The answer is 0,0625 mol.
How many moles are there in 78.4litre oxygen?
4.9 mol
How many moles F2 are required to produce 3.0 moles KrF6 in the equation Kr plus 3F2 producing KrF6?
Given the balanced equation Kr + 3F2 --> KrF6 In order to find how many moles of F2 are needed to produce 3.0 moles of KrF6, we must convert from moles to moles (mol --> mol conversion). 3.0 mol KrF6 * 3 molecules F2 = 9.0 mol F2 --------- 1 molecule F2
How many moles of KBr will be produced from 14.17 moles of BaBr2?
14.17 mol BaBr2 has 2*14.17 mol Br in it, so 28.34 mol KBr can be produced (also 28.34 mol K is needed)
How many moles are in 0.525g of AgCl?
To find the number of moles in 0.525g of AgCl, you need to divide the mass by the molar mass of AgCl. The molar mass of AgCl is 143.32 g/mol. moles = mass / molar mass moles = 0.525g / 143.32 g/mol moles ≈ 0.0037 mol
Is there 143g mol in 6.80g of al2o3?
To determine if there are 143 g/mol in 6.80 g of Al₂O₃, we first need to calculate the molar mass of Al₂O₃. The molar mass of Al₂O₃ is approximately 102 g/mol (with aluminum at about 27 g/mol and oxygen at about 16 g/mol). To find the number of moles in 6.80 g of Al₂O₃, we divide the mass by the molar mass: 6.80 g ÷ 102 g/mol ≈ 0.067 moles. Thus, there are no 143 g/mol in 6.80 g of Al₂O₃; the molar mass is actually around 102 g/mol.
How many moles of aluminum oxide can be made if 5.23 mol Al completely react?
Since the ratio of moles of Al to moles of Al2O3 is 4:2, if 5.23 mol Al completely reacts, 2.615 mol Al2O3 can be made.
How many moles of NaCl are in 737 g of NaCl?
To find the number of moles in 737g of NaCl, first calculate the molar mass of NaCl, which is 58.44 g/mol. Then divide the given mass (737g) by the molar mass to get the number of moles. Number of moles = 737g / 58.44 g/mol ≈ 12.61 moles of NaCl.
How many moles of oxygen must react with 4.50 mol Al?
The answer is 3,375 moles oxygen.
