147 (g) SiO2 / 60.1 (g/mol) = 2.446 mol SiO2
(the molar mass of SiO2 is 60.1 g/mol)
The molar mass of calcium is approximately 40.08 g/mol. To find the number of moles in 147 grams of calcium, you would divide the mass by the molar mass. Once you have the number of moles, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to calculate the number of atoms.
4167.3 grams
First take the weight in pounds and multiply it by 453.59. The resulting number is the weight in grams. In this case the answer is 66679.06 grams.
The density of ethanol at 20 deg C and normal presure is 0.789 g/mL.So the mass of 147 mL is 147*0.789 = 116.0 grams (approx).The density of ethanol at 20 deg C and normal presure is 0.789 g/mL.So the mass of 147 mL is 147*0.789 = 116.0 grams (approx).The density of ethanol at 20 deg C and normal presure is 0.789 g/mL.So the mass of 147 mL is 147*0.789 = 116.0 grams (approx).The density of ethanol at 20 deg C and normal presure is 0.789 g/mL.So the mass of 147 mL is 147*0.789 = 116.0 grams (approx).
The molar mass of calcium is 40.08 g/mol. To calculate the number of atoms in 147 g of calcium, you first need to convert grams to moles, then use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of atoms. The calculation would be: 147 g / 40.08 g/mol = 3.67 mol * 6.022 x 10^23 atoms/mol = 2.21 x 10^24 atoms.
Most lacrosse balls weigh between 140-147 grams.
7.4x10^23 x ( 1 mol AgNO3/ 6.02x10^23) x (169.88g AgNO3/ 1 mol AgNO3)=2.1x10^2g AgNO3no of molecules=7.4x10^23Mr of AgNO3=169.88we can find the no of moles, thereforein 1mol there are 6.02x10^23 molecules7.4x10^23 molecules represent (7.4x10^23/6.02x10^23)molesin theory when we multiply molar mass (Mr) with the no of moles, we obtain the mass of the substance in gram:Mr x no of Mol= Mass in grams(7.4x10^23/6.02x10^23)x169.88= 2.1x10^2
6.66 oz 1 oz = 28.34 grams 1 gram = 0.03 oz
I am sorry, but your question is not answerable. Please repost and tell us what units the "147" is in.
147
how many square feet is 147 yards
dissolve 147 g in enough water to make 1 L of solution